/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 41 Perform the indicated operation,... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Perform the indicated operation, and write each expression in the standard form \(a+\) bi. $$ 6 i^{3}-4 i^{5} $$

Short Answer

Expert verified
-10i

Step by step solution

01

Compute the value of i^3

Recall that \( i \) is the imaginary unit where \( i = \sqrt{-1} \). The powers of \( i \) follow a cyclical pattern: \( i^1 = i \), \( i^2 = -1 \), \( i^3 = -i \), \( i^4 = 1 \), and then it repeats. Therefore, \( i^3 = -i \).
02

Compute the value of i^5

Using the same cyclical pattern, note that \( i^5 \) can be rewritten as \( i^{4+1} = (i^4) \times i = 1 \times i = i \). Therefore, \( i^5 = i \).
03

Substitute the values back into the expression

Replace \( i^3 \) with \( -i \) and \( i^5 \) with \( i \) in the original expression. So, the expression becomes \[ 6(-i) - 4(i) \].
04

Simplify the expression

Simplify the expression \[ 6(-i) - 4(i) \]. This gives \[ -6i - 4i \].
05

Combine like terms

Combine the terms involving \( i \). \[ -6i - 4i = -10i \].
06

Write the expression in standard form

The standard form \( a + bi \) means we identify the real part and the imaginary part. Here the real part is 0, and the imaginary part is \( -10i \). Therefore, the expression in standard form is \[ 0 + (-10i) \] or simply \( -10i \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

imaginary unit
To understand this exercise, you need a firm grasp of the imaginary unit, often represented by the symbol \( i \). The imaginary unit is defined as \( i = \sqrt{-1} \). This might seem odd since you can’t take the square root of a negative number in the realm of real numbers. However, in the imaginary realm, we define this new number, \( i \), to make such mathematics possible. This means that when you square \( i \), you get \( -1 \); mathematically, \( i^2 = -1 \).

Without defining \( i \), much of advanced mathematics, particularly in fields like engineering and physics, wouldn’t be achievable. It’s a crucial concept that extends the number system into a new dimension, giving us the complex numbers.
cyclical pattern of i
The powers of the imaginary unit \( i \) follow a repeating, cyclical pattern. This is essential for solving problems involving higher powers of \( i \). Here's the pattern you see repeatedly:
  • \( i^1 = i \)
  • \( i^2 = -1 \)
  • \( i^3 = -i \)
  • \( i^4 = 1 \)
After \( i^4 = 1 \), the pattern starts over. So, \( i^5 = i \), \( i^6 = -1 \), and so forth.

Knowing this pattern allows you to simplify any power of \( i \) by converting it into one of these four fundamental cases. For example, in the given exercise:
  • \( i^3 = -i \)
  • \( i^5 = i \)
Using these values simplifies the original problem greatly.
standard form of complex numbers
The standard form of a complex number is written as \(a + bi\), where:
  • \(a\) is the real part
  • \(bi\) is the imaginary part, and \(b\) is a real number
In the context of the exercise, we aimed to express the given expression in its standard form.

For instance, in the solution, after computing the values of \(i^3\) and \(i^5\), we substituted them back into the original expression, simplified it, and combined like terms involving \(i\). The result was \(-10i\). Because there is no real part, this is equivalent to saying the real part \(a\) is 0, and the imaginary part \(bi\) is \(-10i\). Thus, the standard form is \(0 + (-10i)\) or just \(-10i\).

Remember, writing complex numbers in their standard form helps to clearly separate the real and imaginary components, making mathematical operations more straightforward.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find the real solutions, if any, of each equation. $$ \sqrt[4]{5 x^{2}-6}=x $$

IQ Tests A standard intelligence test has an average score of \(100 .\) According to statistical theory, of the people who take the test, the \(2.5 \%\) with the highest scores will have scores of more than \(1.96 \sigma\) above the average, where \(\sigma\) (sigma, a number called the standard deviation) depends on the nature of the test. If \(\sigma=12\) for this test and there is (in principle) no upper limit to the score possible on the test, write the interval of possible test scores of the people in the top \(2.5 \%\)

The distance to the surface of the water in a well can sometimes be found by dropping an object into the well and measuring the time elapsed until a sound is heard. If \(t_{1}\) is the time (measured in seconds) that it takes for the object to strike the water, then \(t_{1}\) will obey the equation \(s=16 t_{1}^{2}\), where \(s\) is the distance (measured in feet). It follows that \(t_{1}=\frac{\sqrt{s}}{4}\). Suppose that \(t_{2}\) is the time that it takes for the sound of the impact to reach your ears. Because sound waves are known to travel at a speed of approximately 1100 feet per second, the time \(t_{2}\) to travel the distance \(s\) will be \(t_{2}=\frac{s}{1100} .\) See the illustration. Now \(t_{1}+t_{2}\) is the total time that elapses from the moment that the object is dropped to the moment that a sound is heard. We have the equation $$ \text { Total time elapsed }=\frac{\sqrt{s}}{4}+\frac{s}{1100} $$ Find the distance to the water's surface if the total time elapsed from dropping a rock to hearing it hit water is 4 seconds.

Sewer Bills The village of Oak Lawn charges homeowners \(\$ 23.55\) per quarter- year for sewer usage, plus \(\$ 0.40\) per 1000 gallons of water metered. In 2018 , one homeowner's quarterly bill ranged from a high of \(\$ 36.75\) to a low of \(\$ 30.35 .\) Over what range did metered water usage vary?

A civil engineer relates the thickness \(T,\) in inches, and height \(H,\) in feet, of a square wooden pillar to its crushing load \(L\), in tons, using the model \(T=\sqrt[4]{\frac{L H^{2}}{25}}\). If a square wooden pillar is 4 inches thick and 10 feet high, what is its crushing load?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.