Chapter 1: Problem 104
A student multiplied \(\sqrt{-9}\) and \(\sqrt{-9}\) as follows: $$ \sqrt{-9} \cdot \sqrt{-9}=\sqrt{(-9)(-9)}=\sqrt{81}=9 $$ The instructor marked the problem incorrect. Why?
Short Answer
Expert verified
The correct answer is \-9\. The student's error was in misapplying the square root property to complex numbers.
Step by step solution
01
Understand the Problem
The student multiplied \(\sqrt{-9}\) by \(\sqrt{-9}\) and simplified it incorrectly. The task is to identify the mistake in the student's solution.
02
Recognize Properties of Complex Numbers
Recall that \(\sqrt{-9}\) is not a real number since it involves the square root of a negative number. We need to use the imaginary unit \(\textrm{i}\), where \(\textrm{i} = \sqrt{-1}\). Hence, \(\sqrt{-9} = 3\textrm{i}\).
03
Correct Multiplication
Using \(\sqrt{-9} = 3i\), we multiply the two terms: \(\sqrt{-9} \cdot \sqrt{-9} = 3i \cdot 3i = 9i^2\).
04
Simplify Using Properties of \(\textrm{i}\)
Recall that \(\textrm{i^2} = -1\), so the expression becomes \(9i^2 = 9(-1) = -9\).
05
Conclusion
The correct multiplication yields \(-9\) rather than \(9\). The student incorrectly applied the property of square roots to the complex number.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
imaginary unit
The imaginary unit is a concept in mathematics used to handle the square roots of negative numbers. It is denoted by \(\textrm{i}\), where \(\textrm{i} = \sqrt{-1}\). This might sound strange, because there's no real number whose square is \(-1\). But mathematicians agreed on this notation to simplify equations that involve negative square roots.
When you encounter a negative number under a square root, you can use the imaginary unit to express it. For example, \(\textrm{i}\sqrt{3}\) represents the square root of \(-3\). The main reason for introducing \(\textrm{i}\) is to extend the real number system to the complex number system.
This allows us to solve equations that have no real solutions. For instance, the equation \(x^2 + 1 = 0\) has no real solutions, but it has two complex solutions: \(x = \textrm{i}\) and \(x = -\textrm{i}\). So, by using the imaginary unit, we can work with a broader set of numbers, which is very useful in fields like engineering and physics.
When you encounter a negative number under a square root, you can use the imaginary unit to express it. For example, \(\textrm{i}\sqrt{3}\) represents the square root of \(-3\). The main reason for introducing \(\textrm{i}\) is to extend the real number system to the complex number system.
This allows us to solve equations that have no real solutions. For instance, the equation \(x^2 + 1 = 0\) has no real solutions, but it has two complex solutions: \(x = \textrm{i}\) and \(x = -\textrm{i}\). So, by using the imaginary unit, we can work with a broader set of numbers, which is very useful in fields like engineering and physics.
- Remember: \(\textrm{i}\) is not a real number but an essential part of complex numbers!
square roots of negative numbers
Taking the square root of a negative number traditionally posed a dilemma, but understanding and using the imaginary unit \(\textrm{i} \) solves much of that confusion. In real numbers, the square root of a negative number does not exist. However, in complex numbers, it's possible.
When dealing with a negative number under a square root, convert it using \(\textrm{i}\). For instance, \(\textrm{\sqrt{-9}}\) can be broken down into: \(\sqrt{-9}=\sqrt{9}\cdot\sqrt{-1}=3\textrm{i}\).
This method allows you to simplify and work with these roots easily.
When dealing with a negative number under a square root, convert it using \(\textrm{i}\). For instance, \(\textrm{\sqrt{-9}}\) can be broken down into: \(\sqrt{-9}=\sqrt{9}\cdot\sqrt{-1}=3\textrm{i}\).
This method allows you to simplify and work with these roots easily.
- You must note that when multiplying square roots of negative numbers, using properties of real numbers incorrectly can lead to mistakes.
- As shown in the original problem, treating \(\textrm{\sqrt{-9}}\cdot\textrm{\sqrt{-9}}\) as \(\textrm{\sqrt{81}} = 9\) is incorrect.
- Instead, handle the imaginary unit carefully: \(\textrm{3i}\cdot\textrm{3i} = 9\textrm{i}^2 = 9(-1) = -9\).
properties of i
It’s crucial to fully understand the properties of the imaginary unit \(\textrm{i}\) to work reliably with complex numbers. Here are some fundamental properties:
1. The most basic property is \(\textrm{i} = \sqrt{-1}\).
2. From this, it follows that \(\textrm{i^2} = -1\).
3. Extending further: \(\textrm{i^3} = \textrm{i} \cdot \textrm{i^2} = \textrm{i}(-1) = - \textrm{i}\).
4. Additionally, \(\textrm{i^4} = (\textrm{i^2})^2 = (-1)^2 = 1\). This cycle repeats every four powers.
These properties can be used to simplify complex expressions involving \(\textrm{i}\). For example, understanding \(\textrm{i^2} = -1\) was crucial in correcting the original multiplication problem: \(\textrm{3i} \cdot \textrm{3i} = 9 \textrm{i}^2 = 9(-1)= -9\).
Remembering that \(\textrm{i^2} = -1\) can simplify your problem-solving process greatly and help avoid missteps such as concluding that \(\textrm{\sqrt{-9} \cdot \sqrt{-9} = 9}\). This importance of being careful, especially with squaring and multiplying imaginary numbers, cannot be overstressed.
1. The most basic property is \(\textrm{i} = \sqrt{-1}\).
2. From this, it follows that \(\textrm{i^2} = -1\).
3. Extending further: \(\textrm{i^3} = \textrm{i} \cdot \textrm{i^2} = \textrm{i}(-1) = - \textrm{i}\).
4. Additionally, \(\textrm{i^4} = (\textrm{i^2})^2 = (-1)^2 = 1\). This cycle repeats every four powers.
These properties can be used to simplify complex expressions involving \(\textrm{i}\). For example, understanding \(\textrm{i^2} = -1\) was crucial in correcting the original multiplication problem: \(\textrm{3i} \cdot \textrm{3i} = 9 \textrm{i}^2 = 9(-1)= -9\).
Remembering that \(\textrm{i^2} = -1\) can simplify your problem-solving process greatly and help avoid missteps such as concluding that \(\textrm{\sqrt{-9} \cdot \sqrt{-9} = 9}\). This importance of being careful, especially with squaring and multiplying imaginary numbers, cannot be overstressed.
- Use these properties to transform and simplify expressions efficiently.