Chapter 0: Problem 132
In Problems 129-136, write each number as a decimal. \(9.88 \times 10^{-4}\)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 0: Problem 132
In Problems 129-136, write each number as a decimal. \(9.88 \times 10^{-4}\)
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for free
Expressions that occur in calculus are given. Factor each expression. Express your answer so that only positive exponents occur. $$6 x^{1 / 2}\left(x^{2}+x\right)-8 x^{3 / 2}-8 x^{1 / 2} \quad x \geq 0$$
The period \(T\), in seconds, of a pendulum of length \(l,\) in feet, may be approximated using the formula $$T=2 \pi \sqrt{\frac{l}{32}}$$ Express your answer both as a square root and as a decimal approximation. Find the period \(T\) of a pendulum whose length is 64 feet.
Rationalize the denominator of each expression. Assume that all variables are positive when they appear. $$\frac{2}{\sqrt{3}}$$
Simplify each expression. Assume that all variables are positive when they appear. $$\sqrt{9 x^{5}}$$
The period \(T\), in seconds, of a pendulum of length \(l,\) in feet, may be approximated using the formula $$T=2 \pi \sqrt{\frac{l}{32}}$$ Express your answer both as a square root and as a decimal approximation. Find the period \(T\) of a pendulum whose length is 16 feet.
What do you think about this solution?
We value your feedback to improve our textbook solutions.