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Chapter 35: Problem 1122

What is the probability that the sum 11 will appear in a single throw of 2 dice?

Short Answer

Expert verified
The probability of getting the sum of 11 in a single throw of 2 dice is \(\frac{1}{18}\).

Step by step solution

01

Determine the total possible outcomes of throwing 2 dice

We have 6 possible outcomes for each die (1, 2, 3, 4, 5, and 6). To find the total possible outcomes for the two dice, we multiply the number of outcomes for each die: \(6\times 6= 36\).
02

Determine the favorable outcomes that result in the sum 11

Now we need to find the combinations of die rolls that sum up to 11. By enumerating these combinations, we find there is only one option: (5, 6) or (6, 5).
03

Find the probability of getting the sum 11

To find the probability, we take the number of favorable outcomes and divide by the total possible outcomes. In this case, we get \(\frac{2}{36} = \frac{1}{18}\). So, the probability of getting the sum of 11 in a single throw of 2 dice is \(\frac{1}{18}\).

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Most popular questions from this chapter

A bag contains 4 white balls, 6 black balls, 3 red balls, and 8 green balls. If one ball is drawn from the bag, find the probability that it will be either white or green.

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If a card is drawn from a deck of playing cards, what is the probability that it will be a jack or a ten?

Determine the probability of getting 6 or 7 in a toss of two dice.

A bag contains 10 red, 15 green, and 5 yellow beads. If a single bead is drawn from the bag what is the probability (a) that the bead is red, and (b) that the bead is not red?
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