Chapter 11: Problem 238
If \(\mathrm{f}(\mathrm{x})=-2 \mathrm{x}-5\), find the (a) slope, (b) \(\mathrm{x}\) -intercept, and (c) \(\mathrm{y}\) -intercept, (d) Graph the function
Short Answer
Expert verified
(a) Slope: -2, (b) x-intercept: -2.5, (c) y-intercept: -5, (d) Graph: Start at the point (0,-5) and follow the slope -2; draw a straight line through these points.
Step by step solution
01
(a) Find the slope of the function
The given function is in the form \(f(x) = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept. Comparing with the given function \(f(x) = -2x - 5\), we can see that the slope, \(m = -2\). So, the slope of the function is -2.
02
(b) Find the x-intercept of the function
To find the x-intercept, we need to set the output of the function (f(x)) equal to 0 and solve for x. So, we have:
\[0 = -2x - 5\]
Now, solve for x:
\[2x = -5\]
\[x = -\frac{5}{2}\]
So, the x-intercept of the function is -2.5.
03
(c) Find the y-intercept of the function
As mentioned earlier, the y-intercept of the function is the constant term, i.e., \(b = -5\). So, the y-intercept of the function is -5.
04
(d) Graph the function
To graph the function, start by plotting the y-intercept. Mark a point on the y-axis at -5. Now, use the slope to find the next point on the graph. Since the slope is -2, it means that for every 1 unit increase in x, the y value will decrease by 2 units. From the y-intercept point, move 1 unit to the right and 2 units down, and mark a point. Draw a straight line passing through both points, and extend it in both directions. This is the graph of the function \(f(x) = -2x - 5\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Slope of a Line
The slope of a line is a measure of its steepness and direction. In a linear equation written as \( f(x) = mx + b \), the slope is represented by the coefficient \( m \). This value tells us how much the function's value changes as \( x \) increases by 1 unit.
- A positive slope means the line tilts upward as it moves from left to right. - A negative slope, like in the function \( f(x) = -2x - 5 \), indicates the line tilts downward.
In our case, the slope is \(-2\). This indicates that for each unit increase in \( x \), the value of \( f(x) \) decreases by 2 units. The steeper the slope, the greater the change in \( f(x) \) for each unit change in \( x \). Understanding slope is crucial because it helps predict how variables will interact over different value ranges.
- A positive slope means the line tilts upward as it moves from left to right. - A negative slope, like in the function \( f(x) = -2x - 5 \), indicates the line tilts downward.
In our case, the slope is \(-2\). This indicates that for each unit increase in \( x \), the value of \( f(x) \) decreases by 2 units. The steeper the slope, the greater the change in \( f(x) \) for each unit change in \( x \). Understanding slope is crucial because it helps predict how variables will interact over different value ranges.
X-intercept
The x-intercept is the point where a graph crosses the x-axis. At this specific point, the value of \( f(x) \) is zero. In other words, the x-intercept is the solution to the equation when the output is zero.
To find the x-intercept of the function \( f(x) = -2x - 5 \):
The x-intercept is \(-2.5\). This point is crucial for understanding the function's behavior, as it shows where the function changes from positive to negative or vice versa.
To find the x-intercept of the function \( f(x) = -2x - 5 \):
- Set \( f(x) \) to zero: \( 0 = -2x - 5 \).
- Solve for \( x \): First, add 5 to both sides, resulting in \( 2x = -5 \).
- Then, divide both sides by -2 to isolate \( x \), giving \( x = -\frac{5}{2} \).
The x-intercept is \(-2.5\). This point is crucial for understanding the function's behavior, as it shows where the function changes from positive to negative or vice versa.
Y-intercept
The y-intercept is the point where the graph crosses the y-axis, representing the function's value when \( x \) is zero. It is found directly from the equation \( f(x) = mx + b \).
The y-intercept is simply the constant term \( b \). For the given function, \( f(x) = -2x - 5 \), the y-intercept is \(-5\). This tells us that when \( x = 0 \), \( f(x) \) equals \(-5\).
The y-intercept is simply the constant term \( b \). For the given function, \( f(x) = -2x - 5 \), the y-intercept is \(-5\). This tells us that when \( x = 0 \), \( f(x) \) equals \(-5\).
- This point, \( (0, -5) \), is often the starting reference point for graphing.
- It gives a quick snapshot of the function's initial value.
Graphing Linear Equations
Graphing linear equations involves plotting points and drawing straight lines to represent them visually on a graph. For the equation \( f(x) = -2x - 5 \), the graphing process starts with using known values like the y-intercept and the slope.
- First, plot the y-intercept on the graph at the point \( (0, -5) \).- Use the slope to determine direction and spacing. Remember, our slope of \(-2\) indicates moving 1 unit right and 2 units down from the y-intercept.- From the point \( (0, -5) \), you can place another point at \( (1, -7) \). Connecting these points gives a line representing the function.
Linear equations can be easily graphed once you understand these steps. They provide a visual representation of the equation, allowing for insights into the rate of change and intercepts. This makes predictions and further mathematical operations a lot straightforward.
- First, plot the y-intercept on the graph at the point \( (0, -5) \).- Use the slope to determine direction and spacing. Remember, our slope of \(-2\) indicates moving 1 unit right and 2 units down from the y-intercept.- From the point \( (0, -5) \), you can place another point at \( (1, -7) \). Connecting these points gives a line representing the function.
Linear equations can be easily graphed once you understand these steps. They provide a visual representation of the equation, allowing for insights into the rate of change and intercepts. This makes predictions and further mathematical operations a lot straightforward.