Chapter 1: Problem 9
For each of the following lines in \(\mathbb{R}^{2}\), determine a vector equation and parametric equations. (a) \(x_{2}=3 x_{1}+2\) (b) \(2 x_{1}+3 x_{2}=5\)
Short Answer
Expert verified
(a) Vector: \(\begin{pmatrix} x_1 \\ x_2 \end{pmatrix} = \begin{pmatrix} 0 \\ 2 \end{pmatrix} + t \begin{pmatrix} 1 \\ 3 \end{pmatrix}\), Parametric: \(x_1 = t\), \(x_2 = 3t + 2\); (b) Vector: \(\begin{pmatrix} x_1 \\ x_2 \end{pmatrix} = \begin{pmatrix} 0 \\ \frac{5}{3} \end{pmatrix} + t \begin{pmatrix} 3 \\ -2 \end{pmatrix}\), Parametric: \(x_1 = 3t\), \(x_2 = -2t + \frac{5}{3}\).
Step by step solution
01
Understand the Line Equation (a)
The equation given is of the form \(x_{2} = 3x_{1} + 2\). This represents a line in the slope-intercept form, where the slope \(m = 3\) and the y-intercept \(b = 2\). This indicates the line passes through the point \((0, 2)\).
02
Writing the Vector Equation for (a)
A vector equation of a line that passes through a point can be written as \(\textbf{r} = \textbf{r}_0 + t\textbf{d}\), where \(\textbf{r}_0\) is a point on the line, and \(\textbf{d}\) is a direction vector. From \(x_{2} = 3x_{1} + 2\), we choose \((0, 2)\) as \(\textbf{r}_0\) and a direction vector \((1, 3)\) since increasing \(x_1\) by 1 will increase \(x_2\) by 3. Thus, the vector equation is \(\begin{pmatrix} x_1 \ x_2 \end{pmatrix} = \begin{pmatrix} 0 \ 2 \end{pmatrix} + t \begin{pmatrix} 1 \ 3 \end{pmatrix}\).
03
Derive Parametric Equations from Vector Equation (a)
From the vector equation \(\begin{pmatrix} x_1 \ x_2 \end{pmatrix} = \begin{pmatrix} 0 \ 2 \end{pmatrix} + t \begin{pmatrix} 1 \ 3 \end{pmatrix}\), we can extract the parametric equations: \(x_1 = t\) and \(x_2 = 3t + 2\).
04
Understand the Line Equation (b)
The equation \(2x_{1} + 3x_{2} = 5\) is in the general form of a line in 2D space. To interpret this, we can rearrange it to slope-intercept form: \(x_{2} = -\frac{2}{3}x_{1} + \frac{5}{3}\). This shows a line with a slope of \(-\frac{2}{3}\) and y-intercept \(\frac{5}{3}\), passing through the point \(\left(0, \frac{5}{3}\right)\).
05
Writing the Vector Equation for (b)
For the line \(2x_{1} + 3x_{2} = 5\), choose a point it passes through, e.g., \((0, \frac{5}{3})\), and use a direction vector \((3, -2)\). The vector equation is \(\begin{pmatrix} x_1 \ x_2 \end{pmatrix} = \begin{pmatrix} 0 \ \frac{5}{3} \end{pmatrix} + t \begin{pmatrix} 3 \ -2 \end{pmatrix}\).
06
Derive Parametric Equations from Vector Equation (b)
From the vector equation \(\begin{pmatrix} x_1 \ x_2 \end{pmatrix} = \begin{pmatrix} 0 \ \frac{5}{3} \end{pmatrix} + t \begin{pmatrix} 3 \ -2 \end{pmatrix}\), the parametric equations are \(x_1 = 3t\) and \(x_2 = -2t + \frac{5}{3}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Parametric Equations
Parametric equations are a powerful way to describe geometric objects such as lines in a coordinate space. Instead of representing a line with a single equation, we use a set of equations involving a parameter, often denoted as \(t\), which can take on any real number value. This parameter helps to trace all points on the line as it varies. For instance, for a line given by the vector equation \(\begin{pmatrix} x_1 \ x_2 \end{pmatrix} = \begin{pmatrix} 0 \ 2 \end{pmatrix} + t \begin{pmatrix} 1 \ 3 \end{pmatrix}\), the parametric equations are\[x_1 = t\]\[x_2 = 3t + 2\]These equations mean that for any value of \(t\), the coordinates \(x_1\) and \(x_2\) satisfy the line's equation. Parametric equations offer the flexibility to express curves or lines in a more dynamic way, ideal for computer graphics and physics simulations.
Slope-Intercept Form
The slope-intercept form is a common way to express the equation of a line in 2D space. This form is written as \(x_2 = mx_1 + b\), where \(m\) represents the slope of the line, and \(b\) is the y-intercept, the point where the line crosses the y-axis. For example, the equation \(x_2 = 3x_1 + 2\) highlights a line with a slope \(m = 3\) and y-intercept \(b = 2\).
- Slope (\(m\)): Defines the steepness and direction of the line. A positive slope means the line rises as it moves from left to right, while a negative slope indicates it falls.
- Y-intercept (\(b\)): Provides a starting point on the y-axis from which the line extends according to its slope.
Direction Vector
A direction vector is crucial in writing a vector equation of a line. It indicates the line's general direction, providing a "direction" for the line to follow. In the vector equation of a line \(\textbf{r} = \textbf{r}_0 + t\textbf{d}\), \(\textbf{d}\) is the direction vector, while \(t\) is a scalar parameter. For example, in the line equation \(x_2 = 3x_1 + 2\), the direction vector is \((1, 3)\). This means that for every one unit increase in \(x_1\), \(x_2\) increases by three units, maintaining the line's slope.
- The magnitude of the direction vector doesn't affect the line, only its direction.
- Altering the scalar \(t\) traces different points on the line, creating a broader span of the line's direction.
2D Line Equations
Understanding 2D line equations is fundamental in geometry. These equations define a straight line in a two-dimensional space. Typical forms include the slope-intercept form \(x_2 = mx_1 + b\) and the general form \(Ax_1 + Bx_2 = C\). Transforming between these forms is often necessary for solving problems in algebra and calculus. For example, the equation \(2x_1 + 3x_2 = 5\) can be rewritten as \(x_2 = -\frac{2}{3}x_1 + \frac{5}{3}\) to attain the slope-intercept form.
- Slope-intercept form quickly shows slope and y-intercept.
- General form gives a standard way to write any line equation, useful for theoretical analyses.