Chapter 1: Problem 8
What does it mean, geometrically, if \(\vec{u} \cdot(\vec{v} \times \vec{w})=0\) ?
Short Answer
Expert verified
\(\vec{u}\) lies in the plane of \(\vec{v}\) and \(\vec{w}\).
Step by step solution
01
Define Cross Product
The cross product \(\vec{v} \times \vec{w}\) results in a vector that is perpendicular (orthogonal) to both \(\vec{v}\) and \(\vec{w}\). This vector is normal to the plane formed by \(\vec{v}\) and \(\vec{w}\).
02
Define Dot Product
The dot product \(\vec{u} \cdot (\vec{v} \times \vec{w})\) is a scalar that represents the magnitude of \(\vec{u}\) projected onto the direction of \(\vec{v} \times \vec{w}\).
03
Condition Explanation
If \(\vec{u} \cdot (\vec{v} \times \vec{w}) = 0\), it means that the vector \(\vec{u}\) is either of zero magnitude or orthogonal to the normal vector \(\vec{v} \times \vec{w}\). This makes \(\vec{u}\) parallel to the plane formed by \(\vec{v}\) and \(\vec{w}\).
04
Geometrical Interpretation
Geometrically, the expression \(\vec{u} \cdot (\vec{v} \times \vec{w}) = 0\) indicates that the vector \(\vec{u}\) lies in the same plane as the vectors \(\vec{v}\) and \(\vec{w}\). Because the normal vector is perpendicular to the plane, a zero dot product signifies \(\vec{u}\) is not projecting out of the plane.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cross Product
The cross product is a central concept in vector calculus, particularly useful in three-dimensional space. When you take the cross product of two vectors, such as \( \vec{v} \times \vec{w} \), the result is a new vector. This new vector holds a special place: it is perpendicular (orthogonal) to the original two vectors \( \vec{v} \) and \( \vec{w} \). In simpler terms, it 'sticks out' from the plane that these two vectors form and can be thought of as a 'normal' vector to this plane.
If you imagine \( \vec{v} \) and \( \vec{w} \) as your two hands clapping together, the resulting cross product vector is like the direction in which your arms would stick out while doing so - at a right angle to both.
If you imagine \( \vec{v} \) and \( \vec{w} \) as your two hands clapping together, the resulting cross product vector is like the direction in which your arms would stick out while doing so - at a right angle to both.
- The direction of the cross product follows the right-hand rule. If you point your index finger in the direction of \( \vec{v} \) and your middle finger in the direction of \( \vec{w} \), your thumb will point in the direction of \( \vec{v} \times \vec{w} \).
- The magnitude of the cross product corresponds to the area of the parallelogram formed by \( \vec{v} \) and \( \vec{w} \).
- The cross product is not commutative; \( \vec{v} \times \vec{w} \) is not the same as \( \vec{w} \times \vec{v} \) but rather \( -(\vec{w} \times \vec{v}) \).
Dot Product
The dot product is another fundamental concept in vector calculus, distinct from the cross product. Instead of resulting in a vector, the dot product \( \vec{u} \cdot (\vec{v} \times \vec{w}) \) yields a scalar value. You'll often hear it being referred to as the 'inner product'.
This scalar represents how much one vector, say \( \vec{u} \), 'leans' in the direction of another vector. In the expression \( \vec{u} \cdot (\vec{v} \times \vec{w}) \), if the result is zero, this indicates that \( \vec{u} \) does not 'lean' in the direction of the cross product vector. In other words, the projection of \( \vec{u} \) onto the direction of \( \vec{v} \times \vec{w} \) contributes nothing, hence making the dot product zero.
This scalar represents how much one vector, say \( \vec{u} \), 'leans' in the direction of another vector. In the expression \( \vec{u} \cdot (\vec{v} \times \vec{w}) \), if the result is zero, this indicates that \( \vec{u} \) does not 'lean' in the direction of the cross product vector. In other words, the projection of \( \vec{u} \) onto the direction of \( \vec{v} \times \vec{w} \) contributes nothing, hence making the dot product zero.
- The dot product can be calculated as \( |\vec{u}| |\vec{a}| \cos(\theta) \), where \( \theta \) is the angle between \( \vec{u} \) and \( \vec{a} \).
- A zero value for a dot product implies that the two vectors are orthogonal (perpendicular to each other).
- The dot product is commutative, so \( \vec{a} \cdot \vec{b} = \vec{b} \cdot \vec{a} \).
Orthogonal Vectors
When discussing vectors, orthogonality is a simple yet powerful concept. Two vectors are said to be orthogonal if they are perpendicular to each other. Geometrically, this means that they form a right angle where they meet.
In mathematical terms, if you have two vectors, \( \vec{a} \) and \( \vec{b} \), they are orthogonal if their dot product equals zero: \( \vec{a} \cdot \vec{b} = 0 \). This indicates that there is no component of one vector in the direction of the other.
Orthogonality appears frequently in different mathematical contexts, not just in vector calculus:
In mathematical terms, if you have two vectors, \( \vec{a} \) and \( \vec{b} \), they are orthogonal if their dot product equals zero: \( \vec{a} \cdot \vec{b} = 0 \). This indicates that there is no component of one vector in the direction of the other.
Orthogonality appears frequently in different mathematical contexts, not just in vector calculus:
- It plays a critical role in defining orthogonal bases in linear algebra, which can greatly simplify calculations and transformations.
- In physics, orthogonal forces, like those acting on an object moving in a different direction, don't affect each other's results.
- In geometrical interpretation, orthogonality assures independence between directions.