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Show that if \(x\) is rational and \(y\) is irrational, then \(x+y\) is irrational. Show that if, in addition, \(x \neq 0\), then \(x y\) is irrational.

Short Answer

Expert verified
If \(x\) is rational and \(y\) is irrational, then \(x+y\) is irrational; if \(x\neq 0\), then \(xy\) is irrational.

Step by step solution

01

Understand the Definitions

A rational number can be expressed as a fraction \( \frac{a}{b} \) where \( a \) and \( b \) are integers and \( b eq 0 \). An irrational number cannot be expressed in such a way. For example, \( \sqrt{2} \) is irrational.
02

Express Assumptions

Let \( x = \frac{a}{b} \) be a rational number and \( y \) be an irrational number. We need to show that \( x + y \) is irrational and, if \( x eq 0 \), that \( xy \) is irrational.
03

Proof by Contradiction for Addition

Assume that \( x+y \) is rational, i.e., \( x+y = \frac{c}{d} \) where \( c \) and \( d \) are integers, \( d eq 0 \). Then \( y = \frac{c}{d} - \frac{a}{b} \). Since the subtraction of two rational numbers is rational, \( y \) should be rational, leading to a contradiction. Therefore, \( x+y \) must be irrational.
04

Verify Product Condition

Consider \( xy \) where \( x eq 0 \). Suppose \( xy \) was rational, meaning \( xy = \frac{e}{f} \) for some integers \( e \) and \( f \). Then \( y = \frac{e}{f} \cdot \frac{b}{a} \) is rational because it is a product of rational numbers, leading to a contradiction since \( y \) is assumed irrational. Thus, \( xy \) is also irrational.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rational Numbers
Rational numbers are a fundamental concept in mathematics. These are numbers that can be expressed as the quotient or fraction \( \frac{a}{b} \), where \( a \) and \( b \) are integers, and \( b eq 0 \). This means rational numbers include positive integers, negative integers, and simple fractions.
For example:
  • The number 5 is rational because it can be expressed as \( \frac{5}{1} \).
  • The fraction \( \frac{1}{2} \) is also rational.
  • Decimal numbers like 0.75 are rational because they can be rewritten as \( \frac{3}{4} \).
Understanding rational numbers is crucial for distinguishing them from their complementary set, the irrational numbers. Unlike rational numbers, irrational numbers cannot be represented as simple fractions. They are numbers like \( \sqrt{2} \) or \( \pi \) which have non-repeating and non-terminating decimal expansions.
Proof by Contradiction
Proof by contradiction is a powerful and widely used mathematical technique for proving statements. The method starts by assuming that the statement we want to prove is false. Then, through logical deductions, we arrive at a contradiction that conflicts with known facts or assumptions. This contradiction implies that our initial assumption must have been wrong, thus proving that the original statement is true.
In the exercise, to prove that the sum of a rational number \( x \) and an irrational number \( y \) is irrational, we assumed the contrary. We assumed \( x+y \) was rational, meaning it could be represented as \( \frac{c}{d} \). By rearranging terms to express \( y \) in terms of rational numbers, we found that it would mean \( y \) is rational – a contradiction since we know \( y \) is irrational.
Proof by contradiction helps in such cases where direct proof construction is challenging, by leveraging contradictions to strengthen the logic of the argument.
Addition and Multiplication of Irrational Numbers
The behavior of irrational numbers during addition and multiplication can lead to some interesting results. When a rational number \( x \) is added to an irrational number \( y \), the result \( x+y \) remains irrational. This is because if \( x+y \) were rational, then \( y \) could be expressed as the subtraction of two rational numbers, contradicting its irrationality.
Similarly, consider the product of a rational number \( x \) (where \( x eq 0 \)) and an irrational number \( y \). If their product \( xy \) were rational, then \( y \) could be written as the division of two rational numbers, again a contradiction because \( y \) is irrational.
These concepts reinforce the idea that irrational numbers do not easily "transform" into rational numbers under basic arithmetic operations with rational numbers. Understanding these properties helps in deeper explorations of numerical systems and constructing more complex mathematical proofs.

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