Chapter 9: Problem 20
Solve each system. $$ \left\\{\begin{array}{r} 4 x+y-z=8 \\ x-y+2 z=3 \\ 3 x-y+z=6 \end{array}\right. $$
Short Answer
Expert verified
\(x = 1\), \(y = \frac{3}{2}\), \(z = 1\)
Step by step solution
01
Choose a Variable to Eliminate
We'll start by eliminating the variable \(y\) from the equations. This will simplify our system. Begin by focusing on the first and second equations.
02
Eliminate y from First and Second Equations
Multiply the second equation by 1 to keep it the same:\[ x - y + 2z = 3 \]Then subtract it from the first equation:\[ (4x + y - z) - (x - y + 2z) = 8 - 3 \]Simplifying, we get:\[ 3x + 2y - 3z = 5 \]Eliminate \(y\) from the first and third equations next.
03
Eliminate y from First and Third Equations
To eliminate \(y\) from the first and third equations:Multiply the third equation by 1 to keep it the same:\[ 3x - y + z = 6 \]Subtract it from the first equation:\[ (4x + y - z) - (3x - y + z) = 8 - 6 \]Simplifying, we get:\[ x + 2y - 2z = 2 \]
04
Solve the New System
Now, solve the new system of equations obtained in Step 2 and Step 3:1. \(3x + 2z = 5\)2. \(x + 2y - 2z = 2\)Use these two equations to find values for \(x\) and \(z\).
05
Solve for x and z
From the equation \(3x + 2z = 5\), express \(z\) in terms of \(x\):1. \(2z = 5 - 3x\)2. \(z = \frac{5 - 3x}{2}\)Substitute \(z = \frac{5 - 3x}{2}\) into the second equation \(x + 2y - 2z = 2\) and solve for \(y\).
06
Substitute and Solve
Substitute \(z = \frac{5 - 3x}{2}\) into \(x + 2y - 2z = 2\):\[ x + 2y - 2(\frac{5 - 3x}{2}) = 2 \]Simplify:\[ x + 2y - (5 - 3x) = 2 \]\[ x + 2y - 5 + 3x = 2 \]\[ 4x + 2y = 7 \]Now solve for \(y\).
07
Solve for y
Divide the equation \(4x + 2y = 7\) by 2 to simplify:\[ 2x + y = \frac{7}{2} \]Solving for \(y\):\[ y = \frac{7}{2} - 2x \]Now, substitute this value back into the expression for \(z\) to find the actual values of \(x\), \(y\), and \(z\).
08
Solve for x, y, and z
Substitute back the values: if \(x = 1\):\[ y = \frac{7}{2} - 2(1) = \frac{7}{2} - 2 = \frac{3}{2} \]\[ z = \frac{5 - 3(1)}{2} = \frac{5 - 3}{2} = 1 \]So that means \(x = 1\), \(y = \frac{3}{2}\), and \(z = 1\). These values satisfy the conditions.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Elimination Method
The elimination method is a powerful technique used to solve systems of equations. It involves manipulating equations in such a way as to "eliminate" one of the variables. This simplifies the system and makes it easier to solve. By strategically adding or subtracting equations, one variable can be removed, leaving a simpler system behind.
In the given exercise, we are tackling a system of three equations:
In the given exercise, we are tackling a system of three equations:
- \( 4x + y - z = 8 \)
- \( x - y + 2z = 3 \)
- \( 3x - y + z = 6 \)
Solve for Variables
Once a variable is eliminated, the focus shifts to solving for the remaining variables. Now that we've eliminated \( y \), the system reduces:
Next, substituting this expression for \( z \) into the second equation \( x + 2y - 2z = 2 \), we solve for \( y \). By simplifying, we get \( 4x + 2y = 7 \), which further simplifies to \( y = \frac{7}{2} - 2x \).
These manipulations bring us to a point where only straightforward algebra is needed, leading us to the precise values for the variables, aligning perfectly with the solution requirements.
- \( 3x + 2z = 5 \)
- \( x + 2y - 2z = 2 \)
Next, substituting this expression for \( z \) into the second equation \( x + 2y - 2z = 2 \), we solve for \( y \). By simplifying, we get \( 4x + 2y = 7 \), which further simplifies to \( y = \frac{7}{2} - 2x \).
These manipulations bring us to a point where only straightforward algebra is needed, leading us to the precise values for the variables, aligning perfectly with the solution requirements.
Step-by-Step Solution
Breaking down the solution into smaller, manageable steps is crucial to understanding. Here's a structured walkthrough:
**Step 1:** Choose which variable to eliminate. In our problem, we've opted for \( y \). Focusing on equations with \( y \), like the first and second, aligns the coefficients effectively.**Step 2:** Eliminate \( y \) by subtracting one equation from the other. For example, subtract \( (x - y + 2z) \) from \( (4x + y - z) \) to achieve simplification.**Step 3:** Create a new system from these elimination steps, such as \( 3x + 2z = 5 \), that does not include \( y \). Use this to solve for another variable in terms of another one, say \( z \) in terms of \( x \).**Step 4:** Substitute this relationship into other equations to solve systematically for remaining variables like \( y \), using simplification strategies like dividing through or expressing one variable in terms of the others.
**Step 1:** Choose which variable to eliminate. In our problem, we've opted for \( y \). Focusing on equations with \( y \), like the first and second, aligns the coefficients effectively.**Step 2:** Eliminate \( y \) by subtracting one equation from the other. For example, subtract \( (x - y + 2z) \) from \( (4x + y - z) \) to achieve simplification.**Step 3:** Create a new system from these elimination steps, such as \( 3x + 2z = 5 \), that does not include \( y \). Use this to solve for another variable in terms of another one, say \( z \) in terms of \( x \).**Step 4:** Substitute this relationship into other equations to solve systematically for remaining variables like \( y \), using simplification strategies like dividing through or expressing one variable in terms of the others.
- Ensure steps are followed in a logical sequence to avoid errors and keep track of each variable's role during the manipulation.