Chapter 6: Problem 93
Factor each trinomial completely. \(4 x^{2}(y-1)^{2}+25 x(y-1)^{2}+25(y-1)^{2}\)
Short Answer
Expert verified
The trinomial factors to \((y-1)^{2}(2x + 5)^{2}\).
Step by step solution
01
Identify Common Factor
The given trinomial is \(4x^{2}(y-1)^{2} + 25x(y-1)^{2} + 25(y-1)^{2}\). Observe that \((y-1)^{2}\) is a common factor for each term.
02
Factor Out the Common Factor
Extract \((y-1)^{2}\) from the trinomial, which gives: \((y-1)^{2}(4x^{2} + 25x + 25)\).
03
Recognize the Perfect Square Trinomial
Identify that the expression inside the parentheses, \(4x^{2} + 25x + 25\), is a perfect square trinomial. It can be rearranged into the form \((2x + 5)^{2}\) since: - \((2x)^{2} = 4x^{2}\), - \(2 \cdot (2x) \cdot 5 = 20x + 5x = 25x\), - \(5^{2} = 25\).
04
Write the Completely Factored Form
Substitute the perfect square trinomial back into the expression to write the fully factored form: \((y-1)^{2}(2x + 5)^{2}\).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Common Factor
When factoring trinomials, one of the first steps is to look for a common factor. A common factor is a term that appears in every part of the expression. Identifying this can significantly simplify the process of factoring.
In the given trinomial, we see that \((y-1)^{2}\) is a common factor in all the terms: \(4x^{2}(y-1)^{2}\), \(25x(y-1)^{2}\), and \(25(y-1)^{2}\). This means that each part of the expression includes \((y-1)^{2}\), making it an ideal candidate to be factored out.
In the given trinomial, we see that \((y-1)^{2}\) is a common factor in all the terms: \(4x^{2}(y-1)^{2}\), \(25x(y-1)^{2}\), and \(25(y-1)^{2}\). This means that each part of the expression includes \((y-1)^{2}\), making it an ideal candidate to be factored out.
- Extracting common factors can simplify the expression.
- It sets the stage for further factoring steps.
Perfect Square Trinomial
A perfect square trinomial is a special pattern which can be factored into a binomial squared. Recognizing these patterns can greatly reduce the complexity of factoring.
In this exercise, once \((y-1)^{2}\) is factored out, we are left with the expression \(4x^{2} + 25x + 25\). This expression is a classic example of a perfect square trinomial.
In this exercise, once \((y-1)^{2}\) is factored out, we are left with the expression \(4x^{2} + 25x + 25\). This expression is a classic example of a perfect square trinomial.
- First, notice that \((2x)^{2} = 4x^{2}\).
- Then we check if the middle term, \(25x\), matches the pattern \(2 imes ext{{first term}} imes ext{{last term}}\).
- Finally, verify that \(5^{2} = 25\) is indeed the last term.
Factoring Techniques
Factoring techniques are the fundamental methods used to break down complex polynomials into simpler expressions.
In the given trinomial, a combination of techniques is applied:
In the given trinomial, a combination of techniques is applied:
- Initial factoring involves finding and removing common factors, in this case, \((y-1)^{2}\), to simplify the trinomial.
- Next, recognizing the structure of a perfect square trinomial helps us use the technique more efficiently.
- Finally, applying these combined techniques results in the completely factored form: \((y-1)^{2}(2x + 5)^{2}\).