Chapter 6: Problem 11
Factor each trinomial completely. $$ x^{2}+22 x+121 $$
Short Answer
Expert verified
The trinomial factors to \((x + 11)^2\).
Step by step solution
01
Identify the trinomial form
The given expression \(x^2 + 22x + 121\) is a quadratic trinomial written in the standard form \(ax^2 + bx + c\). Here, \(a = 1\), \(b = 22\), and \(c = 121\).
02
Check for perfect square trinomial
Check if the trinomial is a perfect square trinomial. A perfect square trinomial is of the form \((ax + b)^2 = a^2x^2 + 2abx + b^2\). Here, notice that \(c = 121\) is a perfect square (\(11^2\)), and similarly, the middle term \(22x\) can be expressed as \(2 imes 11x\). This indicates that the expression might be \((x + 11)^2\).
03
Verify the factorization
To verify that \((x + 11)^2\) is the correct factorization, expand it: \((x + 11)(x + 11) = x^2 + 11x + 11x + 121\). Combine like terms: \(x^2 + 22x + 121\). This matches the original trinomial.
04
Write the factorized expression
Since the expanded form matches the original trinomial, we conclude that the correct factorization of \(x^2 + 22x + 121\) is \((x + 11)^2\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Perfect Square Trinomial
A perfect square trinomial is a special type of quadratic trinomial that can be expressed as the square of a binomial. This means you can write it in the form \((ax + b)^2\).
In general, when expanding \((ax + b)^2\), it results in:
In general, when expanding \((ax + b)^2\), it results in:
- \(a^2x^2\): The square of the first term \((ax)\).
- \(2abx\): Twice the product of the two terms \((2\times ax \times b)\).
- \(b^2\): The square of the second term \((b\).
- The constant term, 121, is a perfect square (11 squared).
- The middle term, 22x, equals twice the product of the square root of the first term \(x\) and the square root of the third term, 11 (i.e., \(2 \times x \times 11\)).
Quadratic Trinomial
A quadratic trinomial is a polynomial with three terms, where the highest degree of the variable is 2. It generally takes the form \(ax^2 + bx + c\), where \(a\), \(b\), and \(c\) are constants. When factoring a quadratic trinomial, the goal is to express it as a product of two binomials.
In this particular exercise, the quadratic trinomial is \(x^2 + 22x + 121\). Here, the coefficients are:
In this particular exercise, the quadratic trinomial is \(x^2 + 22x + 121\). Here, the coefficients are:
- \(a = 1\)
- \(b = 22\)
- \(c = 121\)
Trinomial Factorization
Trinomial factorization is a method used to rewrite a trinomial in a product form, typically involving binomials. The goal of factoring is to break down a complex expression into simpler factors that, when multiplied, produce the original expression. This is particularly useful in solving equations and simplifying expressions.
For the trinomial \(x^2 + 22x + 121\), recognizing it as a perfect square was essential because it allowed for straightforward factorization into \((x + 11)^2\).
To factor trinomials:
For the trinomial \(x^2 + 22x + 121\), recognizing it as a perfect square was essential because it allowed for straightforward factorization into \((x + 11)^2\).
To factor trinomials:
- Examine the signs and terms to determine if it aligns with special cases such as a perfect square.
- Search for two numbers whose product is \(c\) and whose sum is \(b\) when \(a = 1\). If \(a\) is not 1, more complex methods are used, such as the "ac method" or factoring by grouping.
- Once the factors are identified, rewrite the trinomial as a product of two binomials or, if possible, a squared binomial as in the perfect square trinomial.