Chapter 2: Problem 9
Solve. For Exercises 9 and \(10,\) the solutions have been started for you. A 25 -inch piece of steel is cut into three pieces \(s o\) that the second piece is twice as long as the first piece, and the third piece is one inch more than five times the length of the first piece. Find the lengths of the pieces
Short Answer
Step by step solution
Understanding the Problem
Expressing the Lengths of the Other Pieces
Setting Up the Equation
Simplify the Equation
Solving for \(x\)
Find the Lengths of All Pieces
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
linear equations
To understand their utility, think of a situation like this: You have a total amount of 25 inches of steel to be divided into parts in a certain relationship. Linear equations help us create a mathematical model of this situation. Instead of dealing with guesswork, we use equations to link the known value (25 inches) with the unknown pieces. This allows us to precisely calculate each part.
problem-solving strategies
- Label unknowns with variables, often you start by assigning a letter like\( x \) to represent what you are searching for.
- Next, translate the problem's text into a math expression. This involves expressing other quantities using the relationship to the variable.
- Formulate an equation that captures the relationships and constraints given in the problem.
- Finally, solve the equation using algebraic techniques, and check your work by plugging values back into the original equation.
equation setup
In our example, the key was setting up the pieces of the steel because each segment's length depended on the first piece, denoted as\( x \):
- The first piece is\( x \) inches.
- The second piece is twice the first piece,\( 2x \).
- The third piece is one inch more than five times the first piece,\( 5x + 1 \).
algebraic expressions
Take our example for instance: given that the first piece is represented as \( x \), we used rules of algebra to express other parts.
- Second piece: \( 2x \)
- Third piece: \( 5x + 1 \)