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Approximate each logarithm to four decimal places. $$ \log _{8} 6 $$

Short Answer

Expert verified
\( \log_8 6 \approx 0.8617 \).

Step by step solution

01

Change of Base Formula

To approximate the logarithm, we can use the change of base formula: \( \log_b a = \frac{\log_c a}{\log_c b} \). For this exercise, we'll use base 10 (common logarithms). So, \( \log_8 6 = \frac{\log_{10} 6}{\log_{10} 8} \).
02

Calculate \( \log_{10} 6 \)

Using a calculator, find \( \log_{10} 6 \). Entering this into a calculator gives approximately 0.7782.
03

Calculate \( \log_{10} 8 \)

Next, calculate \( \log_{10} 8 \) using a calculator. This is approximately 0.9031.
04

Divide to Find \( \log_8 6 \)

Now, divide the results from Steps 2 and 3: \( \log_8 6 \approx \frac{\log_{10} 6}{\log_{10} 8} = \frac{0.7782}{0.9031} \approx 0.8617 \).
05

Round to Four Decimal Places

The division yields 0.8617, and it is already in four decimal places. Therefore, \( \log_8 6 \approx 0.8617 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Logarithm Approximation
Approximating logarithms involves estimating the value of a logarithm when it's not readily available. In many cases, especially with non-integral bases, we use helpful strategies to get an estimate.
One of the most common methods for logarithm approximation is the use of the Change of Base Formula. This allows us to convert a complex logarithm into a more manageable form. To understand this with an example, consider the logarithm \( \log_{8} 6 \). This doesn't directly appear on standard calculators, so we use the formula \[ \log_b a = \frac{\log_c a}{\log_c b} \] With the base \( c \) often being 10, since it's a common logarithm, we get a simpler calculation: \( \log_8 6 = \frac{\log_{10} 6}{\log_{10} 8} \). This method helps us convert from base 8 to base 10 and simplify our calculation.To approximate \( \log_{10} 6 \) and \( \log_{10} 8 \), calculators can directly compute these values, providing an easy way to arrive at the solution once the formula is applied. This method is frequently utilized due to its convenience and accuracy for approximations.
Common Logarithms
Common logarithms are designed to make calculations simpler by always using base 10 as their point of reference. This means when you deal with common logarithms, you're using \( \log_{10} \) or simply \( \log \).
Most calculators and computational tools default to this base since it aligns with the decimal system, which is our everyday number system.A core advantage of common logarithms is their ability to simplify the understanding and computation of logarithmic values without memorizing various logarithmic bases. For example, in the exercise provided, \( \log_{10} 6 \) simplifies the task of finding \( \log_{8} 6 \).
Using base 10 also allows utilization of precise functions programmed into digital calculators, which directly compute \( \log \) values, providing accurate approximations.Being foundational in numerous mathematical calculations, common logarithms underpin many scientific and engineering concepts, strengthening comprehension by sticking to a universal base.
Base 10 Logarithms
Base 10 logarithms, often expressed as \( \log \), are frequently used in almost every field because of their utility in simplifying very large or very small numbers. This is crucial in scientific notation, where numbers are handled this way.Base 10 aligns perfectly with the decimal system, making it invaluable in real-world calculations. For instance, evaluating \( \log_{10} 6 \) and \( \log_{10} 8 \) in the provided exercise is easy with most calculators as these are ready to compute base 10 values.
Understanding base 10 allows for quick, easy adaptation of logarithmic concepts and the ability to make rapid calculations across various mathematical and applied fields.By knowing that base 10 is the customary logarithm used for scientific calculations, it's easier to interpret and compare results. It aids in approximations like \( \log_{8} 6 \), by converting it into manageable \( \log_{10} \) calculations, thereby making evaluations straightforward through the change of base formula.

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Most popular questions from this chapter

Let \(f(x)=\log _{0.3} x\). Then \(g(x)=0.3^{x}\) is the inverse of \(f(x)\). The ordered pair (3,0.027) is a solution of the function \(g(x)\). a. Write this solution using function notation. b. Write an ordered pair that we know to be a solution of \(f(x)\). c. Use the answer to part (b) and write the solution using function notation.

Psychologists call the graph of the formula \(t=\frac{1}{c} \ln \left(\frac{A}{A-N}\right)\) the learning curve since the formula relates time t passed, in weeks, to a measure \(N\) of learning achieved, to a measure \(A\) of maximum learning possible, and to a measure c of an individual's learning style. Use this formula to answer Exercises 47 through \(50 .\) Round to the nearest whole number. Norman Weidner is learning to type. If he wants to type at a rate of 50 words per minute \((N=50)\) and his expected maximum rate is 75 words per minute \((A=75)\), how many weeks should it take him to achieve his goal? Assume that \(c\) is 0.09 .

The formula \(y=y_{0} e^{k t}\) gives the population size y of a population that experiences a relative growth rate \(k(k\) is positive if growth is increasing and \(k\) is negative if growth is decreasing). In this formula, \(t\) is time in years and \(y_{0}\) is the initial population at time \(0 .\) Use this formula to solve Exercises 55 and \(56 .\) Round answers to the nearest year. (Source for data: U.S. Census Bureau and Federal Reserve Bank of Chicago) In \(2009,\) the population of Michigan was approximately 9,970,000 and decreasing according to the formula \(y=y_{0} e^{-0.003 t}\). Assume that the population continues to decrease according to the given formula and predict how many years after which the population of Michigan will be \(9,500,000 .\) (Hint: Let \(y_{0}=9,970,000 ; y=9,500,000\), and solve for \(t\).)

Find the value of each logarithmic expression. $$ \log _{4} \frac{1}{64} $$

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