Chapter 11: Problem 2
Find the vertex of the graph of each quadratic function by completing the square or using the vertex formula. $$ f(x)=x^{2}+6 x+5 $$
Short Answer
Expert verified
The vertex is \((-3, -4)\).
Step by step solution
01
Identify the Quadratic Coefficients
Recognize the standard form of the quadratic function: \[ f(x) = ax^2 + bx + c \] Here, \( a = 1 \), \( b = 6 \), and \( c = 5 \).
02
Apply the Vertex Formula
The vertex of a parabola given by the function \( f(x) = ax^2 + bx + c \) can be found using the vertex formula \[ x = -\frac{b}{2a} \]. Substitute \( a = 1 \) and \( b = 6 \) to find \( x \): \[ x = -\frac{6}{2(1)} = -3 \].
03
Substitute to Find the y-Coordinate
Use the x-coordinate found to find the corresponding y-coordinate by substituting back into the function:\[ f(-3) = (-3)^2 + 6(-3) + 5 \].Calculate the result:\[ f(-3) = 9 - 18 + 5 = -4 \].
04
State the Vertex Coordinates
The vertex coordinates are given by the \( x \) value and the corresponding \( y \) value found in previous steps. So, the vertex is \((-3, -4)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Function
A quadratic function is a type of function that represents a parabola when graphed on a coordinate plane. It is typically expressed in the standard form:
- If \( a \) is positive, the parabola opens upwards, resembling a "U" shape.- If \( a \) is negative, the parabola opens downwards, forming an inverted "U" shape.
In the given problem, the quadratic function is \( f(x) = x^2 + 6x + 5 \), where \( a = 1 \), \( b = 6 \), and \( c = 5 \). Identifying these coefficients is crucial for solving for the vertex.
- \( f(x) = ax^2 + bx + c \)
- \( a \) is the coefficient of \( x^2 \)
- \( b \) is the coefficient of \( x \)
- \( c \) is the constant term
- If \( a \) is positive, the parabola opens upwards, resembling a "U" shape.- If \( a \) is negative, the parabola opens downwards, forming an inverted "U" shape.
In the given problem, the quadratic function is \( f(x) = x^2 + 6x + 5 \), where \( a = 1 \), \( b = 6 \), and \( c = 5 \). Identifying these coefficients is crucial for solving for the vertex.
Completing the Square
Completing the square is a method used to rewrite a quadratic equation in a "perfect square" form. This helps in identifying the vertex and understanding the function's properties better. To complete the square, consider the quadratic expression \( x^2 + 6x + 5 \).
Follow these simple steps:
Follow these simple steps:
- Take the coefficient of \( x \), which is 6, and divide it by 2 to get 3.
- Square the result: \( 3^2 = 9 \).
- Add and subtract 9, forming a perfect square trinomial: \( (x^2 + 6x + 9) - 9 + 5 \).
- Simplify as: \( (x + 3)^2 - 4 \).
Vertex Formula
The vertex formula provides a straightforward method to find a parabola's vertex without moving to the completing-the-square method. It is rooted in the standard form \( f(x) = ax^2 + bx + c \).
The formula to find the x-coordinate of the vertex is:
To solve our problem:
The formula to find the x-coordinate of the vertex is:
- \( x = -\frac{b}{2a} \)
To solve our problem:
- With \( a = 1 \) and \( b = 6 \), substitute these into the vertex formula: \( x = -\frac{6}{2(1)} = -3 \).
- Find the y-coordinate by plugging \( x = -3 \) back into the original function: \( f(-3) = (-3)^2 + 6(-3) + 5 = -4 \).
Parabola
A parabola is a U-shaped curve that is the graph of a quadratic function. It is a symmetrical shape, either opening upwards or downward depending on the sign of the quadratic coefficient \( a \).
- Symmetry is a key feature, with the axis of symmetry running through the vertex.
- The vertex is the highest or lowest point depending on the parabola's orientation.
- Opens upwards, as the value of \( a \) is positive.
- Has a vertex at \((-3, -4)\), the lowest point on the curve.