/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1 Find the vertex of the graph of ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the vertex of the graph of each quadratic function by completing the square or using the vertex formula. $$ f(x)=x^{2}+8 x+7 $$

Short Answer

Expert verified
The vertex is \((-4, -9)\).

Step by step solution

01

Identify the Quadratic Equation

The given quadratic function is \( f(x) = x^2 + 8x + 7 \). We will use the vertex formula since it is straightforward for this form.
02

Write Down the Vertex Formula

The vertex of any parabola expressed by the equation \( f(x) = ax^2 + bx + c \) can be found using the vertex formula \( x = -\frac{b}{2a} \). Here, \( a = 1 \), \( b = 8 \), and \( c = 7 \).
03

Calculate the x-coordinate of the Vertex

Using the vertex formula, substitute the values of \( a \) and \( b \):\[x = -\frac{8}{2(1)} = -4\]The x-coordinate of the vertex is \( -4 \).
04

Calculate the y-coordinate of the Vertex

Substitute \( x = -4 \) back into the original function to find \( f(-4) \):\[f(-4) = (-4)^2 + 8(-4) + 7\]Calculate step by step:- \((-4)^2 = 16\)- \(8(-4) = -32\)- So \( f(-4) = 16 - 32 + 7 = -9 \)Thus, the y-coordinate of the vertex is \( -9 \).
05

State the Coordinates of the Vertex

Now that we have both coordinates, the vertex of the function \( f(x) = x^2 + 8x + 7 \) is \((-4, -9)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Completing the Square
Completing the square is a method used to transform a quadratic expression into a perfect square trinomial plus a constant. This technique helps in finding the vertex form of a quadratic equation, which makes it easier to identify the vertex of the parabola. In the quadratic function, such as \( f(x) = x^2 + 8x + 7 \), it can initially be hard to see the vertex just by inspection.
To complete the square, you must first ensure the coefficient of \( x^2 \) is 1. Fortunately, in our example, it already is. The next steps are:
  • Take half of the coefficient of \( x \), square it, and add and subtract this square inside the quadratic expression.
  • For \( x^2 + 8x \), half of 8 is 4, and squaring it gives 16, so you add and subtract 16: \( f(x) = (x^2 + 8x + 16) - 16 + 7 \).
  • Rewrite it as a perfect square and simplify: \( f(x) = (x + 4)^2 - 9 \).
Now that it's in vertex form \( (x + 4)^2 - 9 \), the vertex \( (h, k) \) can be easily identified where \( h = -4 \) and \( k = -9 \). The vertex is \((-4, -9)\).
This form shows the vertex and makes sketching the parabola's graph straightforward.
Vertex Formula
The vertex formula is a quick way to find the vertex of a parabola described by the quadratic equation \( ax^2 + bx + c \). This method is often preferred because it's straightforward and doesn’t require rewriting the expression. For a function like \( f(x) = x^2 + 8x + 7 \), which is already in standard form, using the vertex formula can save you time.
The formula to find the x-coordinate of the vertex is \( x = -\frac{b}{2a} \). Here, \( a = 1 \) and \( b = 8 \), so:
  • \( x = -\frac{8}{2 \times 1} = -4 \)
This tells us the x-coordinate of the vertex is \( -4 \). To find the y-coordinate, substitute \( x = -4 \) into the function:
  • Calculate: \( f(-4) = (-4)^2 + 8(-4) + 7 = -9 \)
Therefore, the y-coordinate is \( -9 \). Thus, the vertex is located at \((-4, -9)\).
The vertex formula swiftly leads you to the vertex without additional computations, making it efficient for parabolas in standard form.
Quadratic Function Graph
A quadratic function graph is a type of U-shaped curve known as a parabola. The quadratic equation \( f(x) = x^2 + 8x + 7 \) portrays this with its graph showing symmetry around its vertex. By identifying the vertex and the axis of symmetry, you can easily sketch the graph.
The vertex of a quadratic function \( (h, k) \) is not just a point on the graph. It tells us where the parabola changes direction. In our specific example, \((-4, -9)\) is the lowest point (unless the parabola is upside down, which applies to functions with a negative leading coefficient).
Here are some crucial characteristics of a quadratic graph:
  • The axis of symmetry is a vertical line through the vertex, for \( x = -4 \) in our example.
  • The direction of the parabola's opening is upward because the \( x^2 \) term is positive.
  • The vertex is the minimum point of the graph for upward-facing parabolas.
Knowing these features allows you to draw the parabola accurately by plotting the vertex, direction of opening, and symmetry, giving a clear visual representation of the function.

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