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91Ó°ÊÓ

Write each expression in the form \(a+b i .\) $$ i^{6}+i^{8} $$

Short Answer

Expert verified
The expression simplifies to \(0 + 0i\).

Step by step solution

01

Understand the Problem

We are asked to express the given complex expression, \(i^6 + i^8\), in the standard form \(a + bi\). This involves simplifying the powers of the imaginary unit \(i\) and then combining the results.
02

Simplify Powers of i

Recall that the imaginary unit \(i\) satisfies \(i^2 = -1\). From this, we can find that other powers of \(i\) are periodic: \(i^3 = -i\), \(i^4 = 1\), \(i^5 = i\), and so on. Generally, \(i^n = i^{(n \, \text{mod} \, 4)}\).
03

Simplify i^6

Express \(i^6\) in terms of \(i^4\) and \(i^2\), as \(i^6 = i^4 \times i^2\). Since \(i^4 = 1\) and \(i^2 = -1\), we have \(i^6 = 1 \times -1 = -1\).
04

Simplify i^8

Express \(i^8\) in terms of \(i^4\), as \(i^8 = (i^4)^2\). Since \(i^4 = 1\), \(i^8 = 1^2 = 1\).
05

Add the Simplified Terms

Combine the results from Steps 3 and 4: \(i^6 + i^8 = -1 + 1 = 0\).
06

Write in a + bi Form

Express the final result in the form \(a + bi\). Since the expression simplifies to 0, this is equivalent to \(0 + 0i\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Imaginary Unit
The imaginary unit, commonly represented by the symbol \(i\), is a fundamental concept in complex numbers. Its defining property is that it satisfies the equation \(i^2 = -1\). This property is essential because it allows for the existence of complex numbers, which are numbers of the form \(a + bi\), where \(a\) and \(b\) are real numbers, and \(i\) is the imaginary unit.

When dealing with the imaginary unit, we must remember that it isn't a real number. Instead, it's an extension of the real number system, created to solve equations that have no real solutions. For example, the equation \(x^2 + 1 = 0\) cannot be solved using real numbers, but it can be solved using complex numbers, where \(x = i\) and \(x = -i\). This solution stems directly from the definition of \(i\).
  • \(i^1 = i\) - It simply remains the imaginary unit.
  • \(i^2 = -1\) - This key property is the basis for all subsequent simplifications and calculations involving \(i\).
Powers of i
Understanding the powers of \(i\) is crucial when working with complex numbers, particularly in simplifying complex expressions. The powers of \(i\) repeat in a cycle of four, making memorization and simplification easier.

Here's the cycle:
  • \(i^1 = i\)
  • \(i^2 = -1\)
  • \(i^3 = -i\)
  • \(i^4 = 1\)
After \(i^4\), the powers repeat:
  • \(i^5 = i\)
  • \(i^6 = -1\)
  • \(i^7 = -i\)
  • \(i^8 = 1\)
This cycle allows us to simplify any power of \(i\) by reducing it using modulo 4. For instance, the original expression \(i^6 + i^8\) becomes easier to manage by recognizing that \(i^6\) corresponds to \(i^2\) and \(i^8\) corresponds to \(i^4\), simplifying further to \(-1 + 1\).
Complex Expression Simplification
Simplifying complex expressions, like \(i^6 + i^8\), involves understanding how to reduce powers of the imaginary unit \(i\) and then combining the results to get an answer in the standard form \(a + bi\). This process is essential when working with more complex forms of equations in mathematics.

To simplify a complex expression:
  • First, utilize the periodic nature of \(i\) to convert higher powers to simpler forms using modulo 4, making calculations more straightforward.
  • Combine the simplified terms by addition or subtraction, as demonstrated in the exercise. Here, \(i^6\) simplified to \(-1\), and \(i^8\) simplified to \(1\).
  • The resultant sum, \(-1 + 1 = 0\), must then be written in the form \(a + bi\). Since the result is \(0\), express it as \(0 + 0i\).
This method breaks down complex maneuvers into simpler steps and makes it possible to handle expressions involving \(i\) with confidence.

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