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Find first five terms of the sequence in which a1=3,an+1=2an+5.

Short Answer

Expert verified

The first five terms of the sequence are3,11,27,59and123.

Step by step solution

01

Step 1. Write down the given information.

The given sequence has a1=3 andan+1=2an+5.

02

Step 2. Evaluating first five terms of the given sequence.

Since, the first term is a1=3 of the given sequence. Therefore, the remaining four terms can be obtained by plugging n=1,2,3,4 to get a2,a3,a4anda5 in the given sequence an+1=2an+5.

For n=1,

an+1=2an+5....Givena1+1=2a1+5....Forn=1a2=23+5....∵a1=3a2=11

For n=2,

an+1=2an+5....Givena2+1=2a2+5....Forn=2a3=211+5....∵a2=11a3=27

For n=3,

an+1=2an+5....Givena3+1=2a3+5....Forn=3a4=227+5....∵a3=27a4=59

For n=4,

an+1=2an+5....Givena4+1=2a4+5....Forn=4a5=259+5....∵a4=59a5=123

Since, a1=3,a2=11,a3=27,a4=59 anda5=123. Therefore, the first five terms of the sequence are 3,11,27,59and123.

03

Step 3. Conclusion.

The first five terms of the sequence are 3,11,27,59and123.

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