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Write the equation of a trigonometric function with a phase shift of -45°.

Short Answer

Expert verified

The equation of the trigonometric function with a phase shift of-45°isy=sinθ+45°+2.

Step by step solution

01

Step 1. Write down the given information.

The given statement is to define the concept of midline of trigonometric graph.

02

Step 2. Concept used.

A function of the form:

y=asinbθ-h+k,y=acosbθ-h+kandy=atanbθ-h+k has phase shift h. And if h>0 the phase shift is to the right and if h<0 then the phase shift is to the left.

03

Step 3. Write the equation of the trigonometric function with a given phase shift.

With the help of concept stated above, the equation of trigonometric function with a phase shift of -45° is written as:

y=asinbθ−h+ky=1sin1θ−−45°+2....Pluggingforh=−45°,a=1,b=1andk=2y=sinθ+45°+2

04

Step 4. Conclusion.

The equation of the trigonometric function with a phase shift of -45° is y=sinθ+45°+2.

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