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The sum of 3 numbers is 20. The second number is 4 times the first and the sum of the first and third is 8. Find the numbers.

Short Answer

Expert verified

The three numbers are3,12,and .5

Step by step solution

01

– First construct a system of equations corresponding to the given situation.

Let the three numbers be x,y,and z.

The sum of three numbers is 20, so, mathematically it can be written as x+y+z=20

The second number is 4 times the first number.

This can be mathematically written as y=4x⇒4x-y=0.

The sum of first and third number is 8.

This can be mathematically written as x+z=8.

So, the system of equations will be:

.x+y+z=204x−y=0x+z=8
02

– Use the elimination method to get the system of equations in two variables.

Add theequationx+y+z=20to the equation4x-y=0.

localid="1647998459082"  â¶Ä‰x+y+z=204x−y+ â¶Ä‰â€‰â¶Ä‰= â¶Ä‰05x+0 â¶Ä‰+z=20

So, the resultant equation is 5x+z=20

Subtract the equation5x+z=20from the equation x+z=8

 â¶Ä‰â€‰â¶Ä‰5x+z=20(−) â¶Ä‰x+z= â¶Ä‰â€‰8_ â¶Ä‰â€‰â¶Ä‰4x+0=12

03

– Find the values of x,y and z.

Solve 4x=12for x:

4x=124x4=124 â¶Ä‰â€‰â¶Ä‰â€‰Dividebothsidesby4x=3

Substitute x=3in4x-y=0and find the value of y

4x−y=04(3)−y=0 â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰Substitute3forx12−y=0 â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰Simplify−y=−12 â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰Subtract12frombothsidesy=12 â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰Dividebothsidesby−1

Substitutelocalid="1647998527720" x=3inx+z=8and find the value ofz

x+z=83+z=8 â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰substitute3forxz=5 â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰Subtract3 f°ù´Ç³¾²ú´Ç³Ù³ó²õ¾±»å±ð²õ

Hence, the solution of the given system of equations isx,y,z=3,12,5.

So, the three numbers are 3,12,and5.

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