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Solve each system of equations

4a−2b+8c=30a+2b−7c=−122a−b+4c=15

Short Answer

Expert verified

The solution set of the given system of equations is infinitely many solutions.

Step by step solution

01

– Use the elimination method to get the system of equations in two variables.

Multiply the equation 2a-b+4c=15by 2and add the new resultant equation to the equation 4a-2b+8c=30.

Perform the subtraction operation on the new two resultant equations

2a− â¶Ä‰b+4c=154a−2b+8c=30_ â¶Ä‰â€‰â¶Ä‰â†’multiplyby2→ â¶Ä‰â€‰â¶Ä‰â€‰â€‰â¶Ä‰â€‰â¶Ä‰4a−2b+8c=30(−)4a−2b+8c=30_ â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰â€‰â¶Ä‰0=0

02

– Conclude the solutions of the given system of equations. 

Here, 0=0. This means the third equation 2a-b+4c=15is a multiple of first equation 4a-2b+8c=30.

So, they are the same plane.

Hence, the solution of the given system of equations is infinitely many solutions

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