91影视

For real numbers $a\text{and}b$with b>0

Absolute value inequality is $\left|a\right|<b$ when $-b<a\text{and}a<b$, and

Absolute value inequality is $\left|a\right|>b$ when $a<-b\text{or}a>b$

For $\left|a\right|<b$, b is always greater than 0

So let n is a positive number

From definition of absolute value inequality, given expression is simplified to

$-n鈮�n\text{and}n鈮�n$

Since, $-n鈮�n$is true only when n is positive real number and $n鈮�n$ is true for all real number.

Solution is 鈥淣on-negative real number鈥� and 鈥淎ll real number鈥�

The solution of compound inequality containing and is the intersection of the solution set of the two inequalities.

So solution is non-negative real number.

As solution is all non-negative real number, so all points on number line start from 0 to $鈭�$ are solution of given inequality.