91Ó°ÊÓ

The solution of the system of linear equations in two variables:

$\begin{array}{l}{a}_{1}x+b_{1}y=c_1\\ a_{2}x+b_{2}y=c_2\end{array}$

by Cramer’s rule is given by role="math" localid="1647337928715" $\left(x,y\right)$where$x=\frac{\left|\begin{array}{cc}{c}_1& b_1\\ c_2& b_2\end{array}\right|}{\left|\begin{array}{cc}{a}_1& b_1\\ a_2& b_2\end{array}\right|}$role="math" localid="1647337922494" $y=\frac{\left|\begin{array}{cc}{a}_1& c_1\\ a_2& c_2\end{array}\right|}{\left|\begin{array}{cc}{a}_1& b_1\\ a_2& b_2\end{array}\right|}$and$\left|\begin{array}{cc}{a}_1& b_1\\ a_2& b_2\end{array}\right|≠0$

The given system of linear equations in two variables is:

$\begin{array}{l}3x−2y=7\\ 4x−y=6\end{array}$

Therefore, by comparing the given system of linear equations with the system of linear equations role="math" localid="1647338045101" $\begin{array}{l}{a}_{1}x+b_{1}y=c_1\\ a_{2}x+b_{2}y=c_2\end{array}$it can be obtained that:

$a_1=3$, $b_1=-2$, $c_1=7$, $a_2=4$, $b_2=-1$ and $c_2=6$.

The value of $x$is given by:

$\begin{array}{c}x=\frac{\left|\begin{array}{cc}7& −2\\ 6& −1\end{array}\right|}{\left|\begin{array}{cc}3& −2\\ 4& −1\end{array}\right|}\\ =\frac{−7−\left(−12\right)}{−3−\left(−8\right)}\\ =\frac{−7+12}{−3+8}\\ =\frac{5}{5}\\ =1\end{array}$

The value of $y$is given by:

$\begin{array}{c}y=\frac{\left|\begin{array}{cc}3& 7\\ 4& 6\end{array}\right|}{\left|\begin{array}{cc}3& −2\\ 4& −1\end{array}\right|}\\ =\frac{18−\left(28\right)}{−3−\left(−8\right)}\\ =\frac{18−28}{−3+8}\\ =\frac{−10}{5}\\ =−2\end{array}$

The values of $x$ and \[y\] are 1 and $-2$ respectively.

The solution of the given system of equations is $\left(1,-2\right)$.