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Chapter 4: Q70. (page 188)

Solve the system of equation.

x+y=鈭�33x+4y=鈭�12

Short Answer

Expert verified

The solution is x=0,y=-3.

Step by step solution

01

Step 1- Consider the equation.

Consider the system of equation

x+y=鈭�3(1)3x+4y=鈭�12(2)

02

Step 2- Step description.

Multiply the equation (1) by 3 such that 3x+3y=-9. (3)

Subtract the equation (3) from the equation (2) as follows:

3x+4y鈭�(3x+3y)=鈭�12鈭�(鈭�9)3x+4y鈭�3x鈭�3y=鈭�12+9y=鈭�3

03

Step 3- Step description.

Substitute the value of y in equation (1).

x+y=鈭�3x+(鈭�3)=鈭�3x鈭�3=鈭�3x=鈭�3+3x=0

Therefore, the solution is x=0,y=-3.

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