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Chapter 4: Q54. (page 166)

Solve each system by using substitution or elimination.

3p+6q=−32p−3q=−9

Short Answer

Expert verified

The solution of the system of equations: 3p+6q=−32p−3q=−9 is -3,1.

Step by step solution

01

- Solve the first equation for p in terms of q

Write the equation 3p+6q=-3in terms of p.

3p+6q=−33p+6q−6q=−3−6q3p=−3−6q3p3=−3−6q3p=−1−2q

02

- Solve for q

Substitute -1-2q for p into equation 2p-3q=-9 so as to obtain the value of q.

2−1−2q−3q=−92−1−22q−3q=−9−2−4q−3q=−9−2−7q+2=−9+2−7q=−7q=1

03

- Solve for p

Now substitute 1 for q into either original equation and solve for p.

3p+61=−33p+6−6=−3−63p=−9p=−3

Therefore, the solution of the system is -3,1.

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