91Ó°ÊÓ

Number the given system of equations.

The first equation is: $y=3x+5$.

When $x=0$,

$\begin{array}{l}y=3\left(0\right)+5\\ =0+5\\ =5\end{array}$

Therefore, when $x=0$, $y=5$.

When $x=-1$,

$\begin{array}{l}y=3\left(−1\right)+5\\ =−3+5\\ =2\end{array}$

Therefore, when $x=-1$, $y=2$

Therefore, the equation $y=3x+5$ is the equation of the line passing through the points $\left(0,5\right)$ and $\left(-1,2\right)$.

The graph of the equation $y=3x+5$ is:

The second equation is: $y=-2x-5$.

When $x=0$,

$\begin{array}{l}y=−2\left(0\right)−5\\ =−0−5\\ =−5\end{array}$

Therefore, when $x=0$, $y=-5$.

When $x=-1$,

$\begin{array}{l}y=−2\left(−1\right)−5\\ =2−5\\ =−3\end{array}$

Therefore, when $x=-1$, $y=-3$

Therefore, the equation $y=-2x-5$ is the equation of the line passing through the points $\left(0,-5\right)$ and $\left(-1,-3\right)$.

The graph of the equation $y=-2x-5$ is:

The graph of the equations $y=3x+5$ and $y=-2x-5$ is:

From the graph of the equations $y=3x+5$ and $y=-2x-5$, it can be noticed that the lines are intersecting at a point $\left(-2,-1\right)$.

The solution of the system of linear equations in two variables is given by the intersection point of the lines.

Therefore, the solution of the given system of equations is $\left(-2,-1\right)$.

That implies, the solution of the given system of equation is $x=-2$ and $y=-1$.