91Ó°ÊÓ

Since, an ordered pair is represented by a column matrix and triangle has 3 ordered pair on vertices so required matrix has 2 rows and 3 columns.

Coordinates of $\mathrm{Δ}ABC$are $A\left(-4,2\right),B\left(-4,-3\right),\text{and}C\left(3,-2\right)$, so its vertex matrix is $\left[\begin{array}{ccc}-4& -4& 3\\ 2& -3& -2\\ & & \end{array}\right]$

Again, Coordinates of $\mathrm{Δ}A\text{'}B\text{'}C\text{'}$are $A\text{'}\left(-12,6\right),B\text{'}\left(-12,-9\right),\text{and}C\text{'}\left(9,-6\right)$, so its vertex matrix is $\left[\begin{array}{ccc}-12& -12& 9\\ 6& -9& -6\\ & & \end{array}\right]$

Vertex matrix of triangle after dilation is product of scale factor $\left(k\right)$ with vertex matrix of given triangle as shown below

$k×\left[\begin{array}{ccc}−4& −4& 3\\ 2& −3& −2\end{array}\right]=\left[\begin{array}{ccc}−12& −12& 9\\ 6& −9& −6\end{array}\right]$

Multiply scale factor $\left(k\right)$with vertex matrix of given triangle and equate it equal to vertex matrix of image. As both matrices are equal so corresponding elements are equal, so equate corresponding elements to get value of k as shown below

$\begin{array}{c}\left[\begin{array}{ccc}−4k& −4k& 3k\\ 2k& −3k& −2k\end{array}\right]=\left[\begin{array}{ccc}−12& −12& 9\\ 6& −9& −6\end{array}\right]\\ −4k=−12\\ k=3\end{array}$

So, perimeter of $A\text{'}B\text{'}C\text{'}$ is 3times as that of $ABC$