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Solve each system of equations.

3r-15s+4t=-579r+45s-t=26-6r+10s+3t=-19

Short Answer

Expert verified

The solution of given system of equation is -43,35,-11.

Step by step solution

01

– Description of step.

Add 9r+45s-t=26 and -6r+10s+3t=-19.

9r+45s−t−6r+10s+3t=26−193r+55s+2t=7
02

– Description of step.

Subtract 3r-15s+4t=-57 from the obtained equation in step 1 then divide each side of the obtained equation by 2 and solve for s.

3r+55s+2t−3r−15s+4t=7−−573r+55s+2t−3r+15s−4t=64702s−22t=64235s−t=32s=t35+3235
03

– Description of step.

Multiply 3r-15s+4t=-57 by 3 and add obtained equation to 9r+45s-t=26then solve for r.

9r−45s+12t+9r+45s−t=−171+2618r+11t=−14518r=−145−11tr=−14518−1118t
04

– Description of step.

Substitute t35+3235 for sand -14518-1118tfor rinto -6r+10s+3t=-19 find the value of t.

−6−14518−1118t+10t35+3235+3t=−19113+27+3t=−19−1453−64714621t=−160621t=−1606146=−11
05

– Description of step.

Substitute -11 for t into s=t35+3235 and simplify.

s=−1135+3235=−11+3235=35
06

– Description of step.

Substitute -11 for t into r=-14518-1118t and simplify.

r=−14518−1118×−11=−145+12118=−43

Therefore, the solution of given system of equation is -43,35,-11.

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