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Chapter 4: Q38. (page 158)

Solve each system of equations.

3a+2b=275a-7b+c=5-2a+10b+5c=-29

Short Answer

Expert verified

The solution of given system of equation is 7,3,-9.

Step by step solution

01

– Description of step.

Multiply 5a-7b+c=5 by 5 and subtract -2a+10b+5c=-29 from the obtained equation.

25a鈭�35b+5c鈭�鈭�2a+10b+5c=25鈭�鈭�2925a鈭�35b+5c+2a鈭�10b鈭�5c=5425a鈭�35b+2a鈭�10b=5427a鈭�45b=54
02

– Description of step.

Multiply 3a+2b=27by 9 and subtract 27a-45b=54from the obtained equation.

27a+18b鈭�27a鈭�45b=243鈭�5427a+18b鈭�27a+45b=18963b63=18963b=3
03

– Description of step.

Substitute 3 for binto 3a+2b=27and simplify to obtain the value ofa.

3a+23=273a+6=273a3=213a=7
04

– Description of step.

Substitute 3 for b and 7 for ainto 5a-7b+c=5and simplify to obtain the value of c.

57鈭�73+c=535鈭�21+c=514+c=5c=鈭�9

Therefore, the solution of given system of equation is 7,3,-9.

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[730255]鈰�[鈭�2143鈭�52431]

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4.34567
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