91Ó°ÊÓ

The x-intercept is the value of x when $y=0$. Similarly, the y-intercept is the value of y when $x=0$.

The given equation is $4x-3y+8=0$.

Solving for x-intercept,

$4x-3y+8=0$ (Given equation)

$4x-3\left(0\right)+8=0$ (Put $y=0$ in the given equation)

$4x+8=0$ (Simplify)

$4x+8-8=0-8$ (Subtract 8 from both sides)

$4x=-8$ (Simplify)

$\frac{4x}{4}=\frac{-8}{4}$ (Divide both sides by 4)

$x=-2$ (Simplify)

So, the x-intercept is $-2$and the graph crosses the x-axis at the point $\left(-2,0\right)$.

Similarly, solving for y-intercept,

$4x-3y+8=0$ (Given equation)

$4\left(0\right)-3y+8=0$(Put $x=0$ in the given equation)

$-3y+8=0$ (Simplify)

$-3y+8-8=0-8$ (Subtract 8 from both sides)

$-3y=-8$ (Simplify)

$\frac{-3y}{-3}=\frac{-8}{-3}$ (Divide both sides by -3)

$y=\frac{8}{3}$(Simplify)

So, the y-intercept is $\frac{8}{3}$ and thus the graph crosses the y-axis at the point $\left(0,\frac{8}{3}\right)$.

Graphing the given equation using the obtained ordered pairs,