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Graph the line that satisfies each set of conditions.

Passes through -1,5perpendicular to graph of 5x-3y-3=0.

Short Answer

Expert verified

The graph of the required line is:

Step by step solution

01

Step 1- Given information

A point (-1,5)and an equation 5x-3y-3=0.

02

Step 2- Calculation

From given information,

A point (-1,5)and 5x-3y-3=0

Here, x-intercept is:

5x−3×0=3⇒5x=3⇒x=35

y- intercept is:

5×0−3y=3⇒−3y=3⇒y=−1

Therefore, the line goes to 1 units up and 35 units right then.

So, the slope of the line is 53.

The slope of the perpendicular line is the opposite reciprocal of 53is -35.

Now, start at (-1,5)and go 3 units below and 5 units right then,

We get a new point 4,2.

Now we draw the line which is contained both the points (-1,5) and 4,2.

03

Step 3- Graph of the line

The graph of the required line is:

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