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If n is a prime integer such that2n>19≥78nwhat is one possible value of n?

Short Answer

Expert verified

The one possible value forn is 11.

Step by step solution

01

Step-1 – Apply the concept of prime integers

The set of integers are the positive and negative whole numbers including 0 and is expressed as …,−2,−1,0,1,2,….

The set of prime numbers are those numbers which have only two factors that are 1 and number itself.

02

Step-2 –Solve the inequality

Consider the provided inequality 2n>19≥78n.

Divide the inequality by n.

2nn>19n≥78nn2>19n≥78

Take the reciprocal and reverse the order of inequality.

2nn>19n≥78nn2>19n≥7812<n19≤87

03

Step-3 –Simplify the inequality

Multiply the inequality by 19.

12⋅19<n19⋅19≤87⋅19192<n≤1527

Convert to decimal notation.

9.5<n≤21.71

Now, the prime integers that lie between 9.5 and 21.71 are possible values of n.

Therefore, one prime integer is 11. Because only factors of 11 are 1 and 11 only.

Thus, the one possible value for n is 11.

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