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Graph the line that satisfies each set of conditions.

10. Passes through 4,-2 perpendicular to graph of 3x-2y=6.

Short Answer

Expert verified

The graph of the required line is:

Step by step solution

01

Step 1- Given information

A point (4,-2)and an equation 3x-2y=6.

02

Step 2- Calculation

From given information,

A point (4,-2)and 3x-2y=6

Here, x-intercept is:

3x−2×0=6⇒3x=6⇒x=2

y- intercept is:

3×0−2y=6⇒−2y=6⇒y=−3

Therefore, the line goes to 3units up and 2 units right then.

So, the slope of the line is 32.

The slope of the perpendicular line is the opposite reciprocal of 32is -23.

Now, start at (4,-2)and go 2 units below and 3 units right then,

We get a new point 7,-4.

Now we draw the line which is contained both the points (4,-2) and 7,-4.

03

Step 3- Graph of the line

The graph of the required line is:

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