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State whether the graph of each quadratic function opens up or down. Then state whether the function has a maximum or minimum value.

a.f(x)=3x2+4x−5b.f(x)=−2x2+9c.f(x)=−5x2−8x+2d.f(x)=6x2−5x

Short Answer

Expert verified
  1. The graph of function f(x)=3x2+4x-5 opens up and has a minimum value.
  2. The graph of function f(x)=-2x2+9 opens down and has a maximum value.
  3. The graph of function f(x)=-5x2-8x+2 opens down and has a maximum value.

d. The graph of function f(x)=6x2-5x opens up and has a minimum value.

Step by step solution

01

aStep 1. Use the concept.

The graph of f(x)=ax2+bx+c,a≠0

opens up and has a minimum value when a>0, and

opens down and has a maximum value when a<0

02

Step 2. Given Information.

The given function is f(x)=3x2+4x-5

03

Step 3. Solution

In the function f(x)=3x2+4x-5, we have a=3>0

So, the graph of function f(x)=3x2+4x-5 opens up and has a minimum value.

04

bStep 1. Use the concept.

The graph of f(x)=ax2+bx+c,a≠0

opens up and has a minimum value when a>0, and

opens down and has a maximum value when a<0

05

Step 2. Given Information.

The given function is f(x)=-2x2+9

06

Step 3. Solution.

In the functionf(x)=-2x2+9, we have a=-2<0

So, the graph of function f(x)=-2x2+9 opens down and has a maximum value.

07

cStep 1. Use the concept.

The graph of f(x)=ax2+bx+c,a≠0

opens up and has a minimum value when a>0, and

opens down and has a maximum value when a<0

08

Step 2. Given Information.

The given function is f(x)=-5x2-8x+2

09

Step 3. Solution.

In the function f(x)=-5x2-8x+2, we have a=-5<0

So, the graph of function f(x)=-5x2-8x+2 opens down and has a maximum value.

10

dStep 1. Use the concept.

The graph of f(x)=ax2+bx+c,a≠0

opens up and has a minimum value when a>0, and

opens down and has a maximum value when a<0

11

Step 2. Given Information.

The given function is f(x)=6x2-5x

12

Step 3. Solution.

In the function f(x)=6x2-5x, we have a=6>0

So, the graph of function f(x)=6x2-5x opens up and has a minimum value.

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