Chapter 1: Problem 7
Man zeige, dass die Teilmenge \(\mathbb{Z}+\mathbb{Z} \mathrm{i}=\\{a+b \mathrm{i} \mid a, b \in \mathbb{Z}\\}\) von \(\mathbb{C}\), versehen mit der gewöhnlichen Multiplikation komplexer Zahlen, eine abelsche Halbgruppe mit neutralem Element ist. Ermitteln Sie die Einheiten von \(\mathbb{Z}+\mathbb{Z}\) i.
Short Answer
Step by step solution
Define the Set
Check Associativity
Check for Commutativity
Identify the Identity Element
Determine the Invertible Elements
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Complex Numbers
Complex numbers are often visualized on a plane known as the complex plane, where the x-axis represents the real part and the y-axis represents the imaginary part. This visualization helps us easily perform operations like addition and multiplication.
- Addition: To add two complex numbers \((a + bi)\) and \((c + di)\), just add the real parts and the imaginary parts separately: \((a+c) + (b+d)i\).
- Multiplication: Multiply two complex numbers by expanding the expression \((a + bi)(c + di)\) to get \(ac - bd + (ad + bc)i\).
Abelian Group
The set \(\mathbb{Z} + \mathbb{Z}i\) with the operation of addition forms an abelian group, as adding complex numbers is commutative. However, in this exercise, we focus on multiplication, and multiplication in \(\mathbb{Z} + \mathbb{Z}i\) does not form an Abelian Group, because not every element in the set has an inverse.
- Commutativity: For any two elements \(x\) and \(y\), \(x \cdot y = y \cdot x\).
- Identity Element: In the context of group theory, an Abelian group must have an identity element. Here, the identity for multiplication is \(1\) (i.e., \(1 + 0i\)).
Associativity
For the set \(\mathbb{Z} + \mathbb{Z}i\), multiplication is associative. This is because for any three numbers \((a+bi)\), \((c+di)\), and \((e+fi)\), we have:
- \((x \cdot y) \cdot z = x \cdot (y \cdot z)\)
- Working this out shows that the real and imaginary components match up, confirming associativity.
Commutativity
For complex numbers, such as those in the set \(\mathbb{Z} + \mathbb{Z}i\), we find that multiplication is commutative:
- \((a + bi) \cdot (c + di) = (c + di) \cdot (a + bi)\)
- The results in terms of real and imaginary parts will be equivalent, confirming the commutative property.