Urn \(A\) contains 6 red and 4 black balls and urn \(B\) contains 4 red and 6
black balls. One ball is drawn at random from urn \(A\) and placed in urn \(B\).
Then 1 ball is drawn at random from urn \(B\) and placed in urn \(A\). If 1 ball
is now drawn at random from urn \(A\), the probability that it is found to be
red is
\([\) IIT-1988]
(a) \(\frac{32}{55}\)
(b) \(\frac{21}{55}\)
(c) \(\frac{19}{55}\)
(d) None of these
(a) Let the events are
\(R_{1}\) : 'a red ball is drawn from urn \(A\) and placed in \(B\) '
\(B_{1}:\) 'a black ball is drawn from urn \(A\) and placed in \(B\) '
\(R_{2}:\) 'a red ball is drawn from urn \(B\) and placed in \(A^{\prime}\)
\(B_{2}:\) 'a black ball is drawn from urn \(B\) and placed in \(A\) 'Urn \(A\)
contains 6 red and 4 black balls and urn \(B\) contains 4 red and 6 black balls.
One ball is drawn at random from urn \(A\) and placed in urn \(B\). Then 1 ball is
drawn at random from urn \(B\) and placed in urn \(A\). If 1 ball is now drawn at
random from urn \(A\), the probability that it is found to be red is
\([\) IIT-1988]
(a) \(\frac{32}{55}\)
(b) \(\frac{21}{55}\)
(c) \(\frac{19}{55}\)
(d) None of these
(a) Let the events are
\(R_{1}\) : 'a red ball is drawn from urn \(A\) and placed in \(B\) '
\(B_{1}:\) 'a black ball is drawn from urn \(A\) and placed in \(B\) '
\(R_{2}:\) 'a red ball is drawn from urn \(B\) and placed in \(A^{\prime}\)
\(B_{2}:\) 'a black ball is drawn from urn \(B\) and placed in \(A\) '