Chapter 3: Problem 14
A bag \(X\) contains 2 white and 3 black balls and another bag \(Y\) contains 4 white and 2 black balls. One bag is selected at random and a ball is drawn from it. Then the probability for the ball chosen be white is (a) \(\frac{2}{15}\) (b) \(\frac{7}{15}\) (c) \(\frac{8}{15}\) (d) \(\frac{14}{15}\)
Short Answer
Step by step solution
Determine the probability of selecting each bag
Calculate the probability of drawing a white ball from bag X
Calculate the probability of drawing a white ball from bag Y
Use the law of total probability to find the overall probability of drawing a white ball
Calculate the values and sum the probabilities
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Law of Total Probability
In the case of the problem with the two bags of balls, we're looking to find the probability of drawing a white ball. This law is particularly useful here because it guides us to consider all possible paths to the desired outcome and how likely each path is. To compute the overall probability of picking a white ball, we first need to think about which bag we are drawing from and the likelihood of each possibility.
With the Law of Total Probability, we finds the probability of a white ball by looking at the probability of drawing from each bag and the probability of drawing a white ball from each of those bags. We see this expressed mathematically as:\[ P(\text{white}) = P(\text{white} | X) \cdot P(X) + P(\text{white} | Y) \cdot P(Y) \]Here, each term represents the probability of selecting a specific bag and then drawing a white ball from it. Adding these two probabilities gives the total probability of drawing a white ball.
Random Selection
When one is chosen at random, each has an equal chance of being selected. Therefore, the probability of selecting either bag is simply: \[ P(X) = \frac{1}{2}, \quad P(Y) = \frac{1}{2} \]This concept is crucial in ensuring that our probability calculations are fair and impartial.
If the selection wasn't random, other factors might bias the result, invalidating our calculations. Understanding random selection helps in structuring our probability problems correctly, leading to accurate and reliable results.
Probability Calculation
Let's see how it unfolds in this exercise:- **Probability of Selecting Bag X or Y**: Since either bag can be picked at random, the probability for each is \( \frac{1}{2} \).- **Probability of Drawing a White Ball from Bag X**: Bag X has a total of 5 balls, 2 of which are white. Therefore, the probability is \( \frac{2}{5} \).- **Probability of Drawing a White Ball from Bag Y**: Bag Y contains 6 balls with 4 being white, which gives a probability of \( \frac{4}{6} \), simplified to \( \frac{2}{3} \).These calculations, though simple at first glance, form the core of our prediction about the probability of picking a white ball from either bag. Each probability step is crucial in combining them through the Law of Total Probability to determine the best outcome.