Chapter 1: Problem 6
If a point \(A\left(x_{1}, y_{1}\right), B\left(x_{2}, y_{2}\right), C\left(x_{3}, y_{3}\right)\) are the vertices of an equilateral triangle whose each side is equal to \(k\), then show that $$ \left|\begin{array}{lll} x_{1} & y_{1} & 2 \\ x_{2} & y_{2} & 2 \\ x_{3} & y_{3} & 2 \end{array}\right|^{2}=3 k^{4} $$
Short Answer
Step by step solution
Understand Problem Statement
Set up the Determinant
Calculate the Determinant
Geometric Interpretation
Evaluate the Expression
Finalize the Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Determinant of a Matrix
- Multiply and subtract according to the diagonal rule of Sarrus for this 3x3 case.
- For the matrix \[\begin{pmatrix}x_1 & y_1 & 2 \x_2 & y_2 & 2 \x_3 & y_3 & 2 \end{pmatrix}\] this involves a systematic pattern of multiplying and combining different sets of elements from the matrix.
Area of a Triangle
This represents half of the absolute value of the determinant-like formula, providing a geometric interpretation of the matrix determinant.
- An important aspect of this calculation is understanding how the arrangement of points affects the sign and magnitude of the area computed.
- In our specific problem, it is equated and scaled to fit the properties of equilateral triangles known for their uniform angles and sides.
Properties of Triangles
- All internal angles are 60 degrees, making calculations more straightforward.
- The altitude line divides the triangle into two right triangles, assisting with problem simplification.
- Area can also be calculated with the formula \( \text{Area} = \frac{\sqrt{3}}{4} k^2 \)