The formula \(t=\frac{\log K}{0.045 \log e}\) gives the time \(t\) (in years) that
it will take an investment \(P\) that is compounded continuously at a rate of
4.5\(\%\) to increase to an amount \(K\) times the original principal.
a. Use the formula to complete the table to three decimal places.
$$
\begin{array}{|c|c|c|c|c|c|c|c|}\hline K & {1} & {2} & {3} & {4} & {5} & {10}
& {20} & {30} \\ \hline t & {} & {} & {} & {} & {} & {} \\ \hline\end{array}
$$
b. Use the table to graph the function \(t=\frac{\log K}{0.045 \log e}\)
c. If Paul invests \(\$ 1,000\) in a savings account that is compounded
continuously at a rate of \(4.5 \%,\) when will his investment double? triple?