Chapter 6: Problem 24
In \(15-26,\) write each series in sigma notation. $$ \frac{1}{1 \times 2}+\frac{1}{2 \times 3}+\frac{1}{3 \times 4}+\frac{1}{4 \times 5}+\frac{1}{5 \times 6}+\frac{1}{6 \times 7} $$
Short Answer
Expert verified
\( \sum_{n=1}^{6} \frac{1}{n(n+1)} \)
Step by step solution
01
Analyze the Series Structure
First, identify the pattern in the series. Observe that each term is of the form \( \frac{1}{n(n+1)} \) where \( n \) is an integer that starts from 1 and increases by 1 for each subsequent term.
02
Determine the Range of Summation Index
Determine the smallest and largest values of \( n \) used in the series. The given series starts at \( \frac{1}{1 \times 2} \) which corresponds to \( n = 1 \), and ends at \( \frac{1}{6 \times 7} \) corresponding to \( n = 6 \). Thus the series runs from \( n = 1 \) to \( n = 6 \).
03
Write in Sigma Notation
Using the general form of the terms and the identified range of \( n \), express the series in sigma notation: \[ \sum_{n=1}^{6} \frac{1}{n(n+1)} \]
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Algebraic Series
An algebraic series is essentially a sequence of numbers where each term is determined using a specific algebraic pattern or formula. These series can have patterns based on arithmetic operations like addition, multiplication, division, or exponentiation.
In our exercise, the algebraic series is generated by a pattern involving division, where each term is expressed as \( \frac{1}{n(n+1)} \). Here, each term is calculated by first identifying \( n \), then using it in the term's formula.
In our exercise, the algebraic series is generated by a pattern involving division, where each term is expressed as \( \frac{1}{n(n+1)} \). Here, each term is calculated by first identifying \( n \), then using it in the term's formula.
- The sequence starts with \( n = 1 \), creating the term \( \frac{1}{1 \times 2} \).
- It continues, with each next term using the subsequent integer value of \( n \).
- This pattern follows logically, ensuring a smooth transition between consecutive terms of the series.
Sigma Notation
Sigma notation is a way of writing a long series of terms in a compact and concise form. It uses the Greek letter \( \Sigma \) (sigma) to indicate summation, making it a powerful tool for handling series in mathematics.
In the provided exercise, the series is expressed using sigma notation as \( \sum_{n=1}^{6} \frac{1}{n(n+1)} \), which denotes the sum of the terms calculated from \( n = 1 \) to \( n = 6 \).
In the provided exercise, the series is expressed using sigma notation as \( \sum_{n=1}^{6} \frac{1}{n(n+1)} \), which denotes the sum of the terms calculated from \( n = 1 \) to \( n = 6 \).
- The expression \( \frac{1}{n(n+1)} \) inside the sigma symbol represents the general form of each term in the series.
- The numbers below and above the sigma specify the starting and ending values of the summation index \( n \).
- This notation simplifies the representation of the series and aids in performing algebraic operations more efficiently.
Summation Index
The summation index, often denoted as \( n \), is a placeholder that represents each term's position within a series in sigma notation. This index acts as a variable that varies over a specified range, defining every term in the series.
For our series, the summation index \( n \) starts at 1 and goes up to 6. This dictates that the series includes terms for all integer values of \( n \) between 1 and 6.
For our series, the summation index \( n \) starts at 1 and goes up to 6. This dictates that the series includes terms for all integer values of \( n \) between 1 and 6.
- The start of the summation index, \( n=1 \), corresponds to the term \( \frac{1}{1 \times 2} \).
- Each subsequent term increases the summation index by 1, continuing the pattern.
- Finishing at \( n=6 \) with the term \( \frac{1}{6 \times 7} \), the series covers all terms from 1 through 6.
Mathematical Series Structure
The mathematical series structure refers to the ordered arrangement of numbers where each follows a rule or formula. The structure is fundamental to comprehending the essence and progression of a series.
In the series given in the exercise, each term's structure adheres to the formula \( \frac{1}{n(n+1)} \). This coherent pattern ensures that each part of the series connects seamlessly.
In the series given in the exercise, each term's structure adheres to the formula \( \frac{1}{n(n+1)} \). This coherent pattern ensures that each part of the series connects seamlessly.
- Each term is clearly defined by the formula, involving multiplication and division, crucial for consistency.
- The sequence naturally progresses by adjusting the index \( n \).
- Keeping track of the structure helps in identifying how each part fits into the series as a whole.