Chapter 6: Problem 21
In \(15-22 :\) a. Write each sum as a series. b. Find the sum of each series. $$ 100+\sum_{k=1}^{6} 100\left(\frac{1}{2}\right)^{k} $$
Short Answer
Expert verified
The series is \( 100 + 50 + 25 + 12.5 + 6.25 + 3.125 + 1.5625 \) and the sum is approximately 198.44.
Step by step solution
01
Understand the Given Problem
We have a mathematical expression which consists of two parts. The first part is the constant **100**, and the second part is a summation notation that needs to be expanded into a series. The task is to write it as a series and then find the sum.
02
Expand the Summation Notation
The given summation is \( \sum_{k=1}^{6} 100 \left( \frac{1}{2} \right)^{k} \). This means we need to calculate the sum of the terms 100 multiplied by \( \left( \frac{1}{2} \right)^{k} \) for each integer \( k \) from 1 to 6.
03
Write the Series
Substituting the values of \( k \) from 1 to 6 into the expression, the series becomes: \[ 100 \left( \frac{1}{2} \right)^{1} + 100 \left( \frac{1}{2} \right)^{2} + 100 \left( \frac{1}{2} \right)^{3} + 100 \left( \frac{1}{2} \right)^{4} + 100 \left( \frac{1}{2} \right)^{5} + 100 \left( \frac{1}{2} \right)^{6} \]
04
Calculate Each Term of the Series
The terms are calculated as follows:- For \( k=1 \): \( 100 \times \frac{1}{2} = 50 \)- For \( k=2 \): \( 100 \times \frac{1}{4} = 25 \)- For \( k=3 \): \( 100 \times \frac{1}{8} = 12.5 \)- For \( k=4 \): \( 100 \times \frac{1}{16} = 6.25 \)- For \( k=5 \): \( 100 \times \frac{1}{32} = 3.125 \)- For \( k=6 \): \( 100 \times \frac{1}{64} = 1.5625 \)
05
Compute the Total Sum of the Series
Add up all the terms obtained from the previous step:\( 50 + 25 + 12.5 + 6.25 + 3.125 + 1.5625 = 98.4375 \)
06
Add the Constant Term
The problem statement includes an additional constant term of **100**, which must be added to the sum of the series: \( 100 + 98.4375 = 198.4375 \)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Summation Notation
Summation notation is a compact way to express the addition of a sequence of terms. It uses the Greek letter sigma (\( \Sigma \)) to represent the sum. In the given exercise, the summation notation is \( \sum_{k=1}^{6} 100 \left( \frac{1}{2} \right)^{k} \). This tells us to sum the terms \( 100 \left( \frac{1}{2} \right)^{k} \), starting with \( k = 1 \) and ending with \( k = 6 \).
- The expression under the sigma symbol is the general term that will be repeated.
- The numbers below and above the sigma (1 and 6 in this case) denote the first and last values of \( k \).
- By expanding this notation, we perform the calculation: \( 100 \times \left(\frac{1}{2}\right) + 100 \times \left(\frac{1}{4}\right) + ... + 100 \times \left(\frac{1}{64}\right) \)
Series Expansion
Series expansion involves taking an expression in summation notation and writing it out in full. In the example provided, the summation \( \sum_{k=1}^{6} 100 \left( \frac{1}{2} \right)^{k} \) is expanded into a series by substituting values for \( k \) from 1 to 6. This process includes the following steps:
- Replace \( k \) with \( 1 \) to get the first term: \( 100 \times \frac{1}{2} \)
- Replace \( k \) with \( 2 \) to get the second term: \( 100 \times \frac{1}{4} \)
- Continue this pattern until \( k \) equals 6.
Sequence and Series
A sequence is an ordered list of numbers following a particular pattern, while a series is the sum of the terms of a sequence. In this context, the terms obtained from the geometric sequence \( 100, 50, 25, 12.5, 6.25, 3.125, 1.5625 \) build the series we are working with.
- A geometric sequence is one where each term is a constant multiple of the previous term. Here, each term is multiplied by \( \frac{1}{2} \) from the previous term.
- We sum these terms to form the series: \( 50 + 25 + 12.5 + 6.25 + 3.125 + 1.5625 \).
Mathematical Expression
Mathematical expressions are combinations of numbers, symbols, and operation signs that represent a specific value or set of values. In the exercise \( 100+\sum_{k=1}^{6} 100\left(\frac{1}{2}\right)^{k} \), we work with a mathematical expression that includes:
- The constant term \( 100 \)
- A summation part \( \sum_{k=1}^{6} 100\left(\frac{1}{2}\right)^{k} \)