Chapter 6: Problem 20
In \(15-26,\) write each series in sigma notation. $$ 1+\frac{1}{2}+\frac{1}{4}+\frac{1}{16}+\frac{1}{32} $$
Short Answer
Expert verified
The series is \( \sum_{n=0}^{4} \frac{1}{2^n} \).
Step by step solution
01
Identify the Sequence Pattern
First, observe the given sequence: \(1, \frac{1}{2}, \frac{1}{4}, \frac{1}{16}, \frac{1}{32}\). Notice that these terms follow a pattern of fractions, where the numerator is fixed at 1, and the denominator is a power of 2.
02
Determine the General Term
To express the series in sigma notation, identify the general term. Each term can be written as \( \frac{1}{2^n} \). Check that when \(n=0\), the term is 1; when \(n=1\), the term is \(\frac{1}{2}\); and so forth.
03
Define the Sigma Notation
Use the general term identified in the previous step to express the series in sigma notation. Summing from \(n=0\) to \(n=4\) gives all the terms. The sigma notation is:\[ \sum_{n=0}^{4} \frac{1}{2^n} \]
04
Verify the Sigma Notation
Check each term that it corresponds correctly to the original series for each applicable \(n\). For example: for \(n=0\), \( \frac{1}{2^0} = 1 \); for \(n=1\), \( \frac{1}{2^1} = \frac{1}{2} \); up to \(n=4\), \( \frac{1}{2^4} = \frac{1}{16} \). All these calculations confirm that the sigma notation is correct.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Geometric Series
A geometric series is a type of mathematical series where each term is derived from the previous one by multiplying it with a fixed, non-zero number called the "common ratio." In the given sequence, the terms are: 1, \( \frac{1}{2} \), \( \frac{1}{4} \), \( \frac{1}{16} \), and \( \frac{1}{32} \). Here, each term is obtained by multiplying the previous term by \( \frac{1}{2} \).
This consistent multiplying factor of \( \frac{1}{2} \) defines our geometric sequence. The first term in this series is 1, and the common ratio is \( \frac{1}{2} \).
The series continues until the last term, and in sigma notation, this is a concise way to represent infinite or finite terms of a sequence.
This consistent multiplying factor of \( \frac{1}{2} \) defines our geometric sequence. The first term in this series is 1, and the common ratio is \( \frac{1}{2} \).
- First term (a): 1
- Common Ratio (r): \( \frac{1}{2} \)
The series continues until the last term, and in sigma notation, this is a concise way to represent infinite or finite terms of a sequence.
Sequence Pattern
Identifying a sequence pattern involves recognizing the underlying rule that relates the terms of the sequence. In our series, we begin with 1, and proceed to \( \frac{1}{2} \), \( \frac{1}{4} \), and so on.
The obvious pattern is that each term is a fraction with a numerator of 1 and a denominator that is a power of 2.
For example:
Recognizing the pattern aids in simplification and is fundamental in higher-level mathematics where sequences form the basis of more complex functions.
The obvious pattern is that each term is a fraction with a numerator of 1 and a denominator that is a power of 2.
For example:
- 1 can be written as \( \frac{1}{2^0} \)
- \( \frac{1}{2} \) is \( \frac{1}{2^1} \)
- \( \frac{1}{4} \) is \( \frac{1}{2^2} \)
Recognizing the pattern aids in simplification and is fundamental in higher-level mathematics where sequences form the basis of more complex functions.
Exponential Function
An exponential function involves a base being raised to a variable exponent. Exponential functions display rapid growth or decay, depending on whether the base is greater than or less than 1.
In this context, we are dealing with a decay function since each term is a fraction, represented as \( \frac{1}{2^n} \). The exponent \( n \) increases with each subsequent term, which causes the denominator to grow and the fraction to shrink.
This exponential decay is a key feature of the series, and it's well-represented in sigma notation, where the base \( 2 \) raised to any power \( n \) continues the series.
Understanding exponential functions is not only essential for series but also in various real-world applications like population studies, radioactive decay, and financial forecasting.
In this context, we are dealing with a decay function since each term is a fraction, represented as \( \frac{1}{2^n} \). The exponent \( n \) increases with each subsequent term, which causes the denominator to grow and the fraction to shrink.
This exponential decay is a key feature of the series, and it's well-represented in sigma notation, where the base \( 2 \) raised to any power \( n \) continues the series.
Understanding exponential functions is not only essential for series but also in various real-world applications like population studies, radioactive decay, and financial forecasting.
Summation
Summation, often represented with the Greek letter sigma (\( \Sigma \)), is used to denote the sum of a sequence of numbers.
In sigma notation, you will usually see a general term, an upper limit, and a lower limit that indicate the range of terms to sum.
For our series, expressed as \( \sum_{n=0}^{4} \frac{1}{2^n} \), the summation tells us to add up all the terms starting from \( n=0 \) through \( n=4 \).
In sigma notation, you will usually see a general term, an upper limit, and a lower limit that indicate the range of terms to sum.
For our series, expressed as \( \sum_{n=0}^{4} \frac{1}{2^n} \), the summation tells us to add up all the terms starting from \( n=0 \) through \( n=4 \).
- \( n=0 \): \( \frac{1}{2^0} = 1 \)
- \( n=1 \): \( \frac{1}{2^1} = \frac{1}{2} \)
- Through \( n=4 \): \( \frac{1}{2^4} = \frac{1}{16} \)