Chapter 5: Problem 38
In \(38-45,\) find the multiplicative inverse of each of the following in \(a+b i\) form. $$ 1+i $$
Short Answer
Expert verified
The multiplicative inverse of \(1+i\) is \(\frac{1}{2} - \frac{1}{2}i\).
Step by step solution
01
Understanding Multiplicative Inverse
The multiplicative inverse of a complex number in the form \(a + bi\) is a number that, when multiplied with \(a + bi\), results in 1. For a complex number, this is given by \(\frac{1}{a + bi}\). This can be expressed in the form \(c + di\), where \((a + bi)(c + di) = 1\).
02
Express the Inverse in Conjugate Form
The multiplicative inverse \(\frac{1}{a + bi}\) can be rewritten using the conjugate of the denominator. The conjugate of a complex number \(a + bi\) is \(a - bi\). So, multiply the numerator and the denominator of \(\frac{1}{1 + i}\) by the conjugate \(1 - i\).
03
Apply the Conjugate Multiplication
Multiply both the numerator and the denominator by the conjugate: \[ \frac{1}{1 + i} \times \frac{1 - i}{1 - i} = \frac{1 - i}{(1 + i)(1 - i)} \].
04
Simplify the Denominator
The product of a complex number and its conjugate is a real number given by \(a^2 + b^2\). For \(1 + i\) and its conjugate \(1 - i\), this is \(1^2 + 1^2 = 1 + 1 = 2\). Hence, \((1 + i)(1 - i) = 2\).
05
Simplify the Numerator
The numerator \(1 - i\) is left unchanged. The fraction now becomes \(\frac{1 - i}{2}\).
06
Write the Multiplicative Inverse in Standard Form
Divide both the real and imaginary parts by the real denominator: \[ \frac{1}{2} - \frac{1}{2}i \]. Thus, the multiplicative inverse of \(1+i\) is \(\frac{1}{2} - \frac{1}{2}i\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Multiplicative Inverse
A multiplicative inverse is a special number that can "undo" a multiplication operation. For real numbers, this is just the reciprocal, like how the inverse of 5 is \(\frac{1}{5}\). However, for complex numbers, things get a bit more exciting.
In the world of complex numbers, the multiplicative inverse of a complex number \(a + bi\) is another complex number that, when multiplied with \(a + bi\), gives 1. This number is expressed as \(\frac{1}{a + bi}\).
To find this inverse, we often rely on the complex conjugate. By multiplying the numerator and the denominator of \(\frac{1}{a + bi}\) by the conjugate \(a - bi\), we get a real number in the denominator. The result is expressed in the familiar \(c + di\) form.
In the world of complex numbers, the multiplicative inverse of a complex number \(a + bi\) is another complex number that, when multiplied with \(a + bi\), gives 1. This number is expressed as \(\frac{1}{a + bi}\).
To find this inverse, we often rely on the complex conjugate. By multiplying the numerator and the denominator of \(\frac{1}{a + bi}\) by the conjugate \(a - bi\), we get a real number in the denominator. The result is expressed in the familiar \(c + di\) form.
- Remember that the entire goal here is to find that \(c + di\) which gives: \((a + bi)(c + di) = 1\).
- Use of conjugates simplifies this process significantly and is key in working comfortably with these inverses.
Complex Conjugate
The complex conjugate is like a mirror for complex numbers. For any complex number \(a + bi\), its complex conjugate is \(a - bi\).
This intriguing concept is incredibly useful for operations with complex numbers.
This intriguing concept is incredibly useful for operations with complex numbers.
- When you multiply a complex number by its conjugate, you get a real number. This product is determined by the equation \(a^2 + b^2\). For instance, with \(1 + i\) and its conjugate \(1 - i\), the multiplication results in \(1^2 + 1^2 = 2\).
- Using the conjugate helps in simplifying expressions and finding multiplicative inverses.
- It's like the secret weapon for dealing with denominators that involve complex numbers.
Complex Number Multiplication
Multiplying complex numbers is a fascinating journey through both multiplication and addition, involving both real and imaginary parts.
When multiplying two complex numbers \((a + bi)\) and \((c + di)\), you follow a distributive method:
This multiplication technique is essential when dealing with equations involving complex numbers, such as finding the multiplicative inverse or simplifying complex fractions.
When multiplying two complex numbers \((a + bi)\) and \((c + di)\), you follow a distributive method:
- Multiply the real parts together: \(ac\).
- Multiply the real part of the first number by the imaginary part of the second: \(adi\).
- Multiply the imaginary part of the first number by the real part of the second: \(bci\).
- Finally, multiply the imaginary parts together: \(bdi^2\). Remember that \(i^2 = -1\).
This multiplication technique is essential when dealing with equations involving complex numbers, such as finding the multiplicative inverse or simplifying complex fractions.