Chapter 5: Problem 28
In \(19-28 :\) a. Find \(\mathrm{f}(a)\) for each given function. b. Is \(a\) a root of the function? $$ \mathrm{f}(x)=-5 x^{3}+5 x^{2}+2 x+3 \text { and } a=\frac{3}{2} i $$
Short Answer
Expert verified
\( f\left(\frac{3}{2} i \right) \neq 0 \), so \( \frac{3}{2} i \) is not a root.
Step by step solution
01
Finding the value of f(a)
We start by substituting the value of \( a = \frac{3}{2} i \) into the function \( f(x) = -5x^3 + 5x^2 + 2x + 3 \). This means we need to evaluate \( f\left(\frac{3}{2} i\right) = -5 \left(\frac{3}{2} i\right)^3 + 5 \left(\frac{3}{2} i\right)^2 + 2 \left(\frac{3}{2} i\right) + 3 \).
02
Calculating each term
First, calculate \( \left(\frac{3}{2} i\right)^2 = \left(\frac{9}{4}\right) i^2 = -\frac{9}{4} \) because \( i^2 = -1 \). Then calculate \( \left(\frac{3}{2} i\right)^3 = \frac{3}{2} i \cdot \left(-\frac{9}{4}\right) = -\frac{27}{8} i \).
03
Evaluating the polynomial terms
Substitute the calculated values back into the function. Compute the terms: 1. \( -5 \left(-\frac{27}{8}i\right) = \frac{135}{8} i \)2. \( 5 \left(-\frac{9}{4}\right) = -\frac{45}{4} \)3. \( 2 \left(\frac{3}{2}i\right) = 3i \)4. The constant term 3 is already given as 3.
04
Summing up all terms
Combine all the terms to get:\[\frac{135}{8} i - \frac{45}{4} + 3i + 3\]First, convert all terms to have a common denominator:\[\frac{135}{8} i + \frac{24}{8} i - \frac{90}{8} + \frac{24}{8}\]Combine the like terms:\[\left(\frac{159}{8} i\right) + \left(-\frac{66}{8}\right)\]
05
Final computation and conclusion
The final result after combining all terms gives us \( \frac{159}{8}i - \frac{66}{8} \). Since this is not zero, we conclude that \( f(a) eq 0 \).
06
Conclusion on whether a is a root
Since \( f(a) eq 0 \), \( a = \frac{3}{2} i \) is not a root of the function \( f(x) = -5x^3 + 5x^2 + 2x + 3 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polynomial Evaluation
Evaluating a polynomial is all about substituting a given number, which could be real or complex, into the polynomial expression and simplifying it. In this exercise, we evaluated the polynomial function \( f(x) = -5x^3 + 5x^2 + 2x + 3 \) by replacing \( x \) with \( a = \frac{3}{2} i \). This means we're plugging the complex number \( \frac{3}{2} i \) where \( x \) is, and solving the expression.
- First, substitute the complex number into each term of the polynomial.
- Calculate each term separately, especially when dealing with powers, as these will involve multiplying the complex number by itself.
- Use the property of the imaginary unit \( i \), where \( i^2 = -1 \), to simplify calculations.
Roots of Polynomials
The roots of a polynomial are the values of \( x \) that make the polynomial equal to zero. If substituting \( a \) into \( f(x) \) results in zero, then \( a \) is indeed a root of the polynomial \( f(x) \).
- Substitute \( a \) into the polynomial.
- Calculate the expression to find \( f(a) \).
- If \( f(a) = 0 \), then \( a \) is a root; otherwise, it is not.
Imaginary Unit
The imaginary unit, denoted as \( i \), is a fundamental concept in complex numbers. It is defined as the square root of negative one: \( i^2 = -1 \).
- When using \( i \) in calculations, remember this squaring property.
- In expressions, whenever you find \( i^2 \), replace it with \(-1\) to simplify the computation.