Chapter 5: Problem 10
In \(3-14\) , use the quadratic formula to find the roots of each equation. Irrational roots should be written in simplest radical form. $$ x^{2}+2 x=4 $$
Short Answer
Expert verified
The roots are \( x = -1 + \sqrt{5} \) and \( x = -1 - \sqrt{5} \).
Step by step solution
01
Write the Equation in Standard Form
The given equation is \( x^2 + 2x = 4 \). To use the quadratic formula, the equation must be in the standard form \( ax^2 + bx + c = 0 \). Subtract 4 from both sides to get \( x^2 + 2x - 4 = 0 \).
02
Identify Coefficients
In the equation \( x^2 + 2x - 4 = 0 \), identify the coefficients: \( a = 1 \), \( b = 2 \), and \( c = -4 \).
03
Write the Quadratic Formula
The quadratic formula to find the roots of \( ax^2 + bx + c = 0 \) is given by: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \].
04
Substitute the Coefficients into the Formula
Substitute \( a = 1 \), \( b = 2 \), and \( c = -4 \) into the quadratic formula: \[ x = \frac{-2 \pm \sqrt{2^2 - 4(1)(-4)}}{2(1)} \].
05
Simplify the Expression under the Square Root
Calculate the expression under the square root (the discriminant): \( b^2 - 4ac = 2^2 - 4(1)(-4) = 4 + 16 = 20 \). The expression becomes \[ x = \frac{-2 \pm \sqrt{20}}{2} \].
06
Simplify the Square Root
Simplify \( \sqrt{20} \). Recall that \( \sqrt{20} = \sqrt{4 \times 5} = \sqrt{4} \times \sqrt{5} = 2\sqrt{5} \). Substitute back into the expression: \[ x = \frac{-2 \pm 2\sqrt{5}}{2} \].
07
Simplify the Entire Expression
Divide each term in the numerator by 2: \[ x = \frac{-2}{2} \pm \frac{2\sqrt{5}}{2} \]. This simplifies to \[ x = -1 \pm \sqrt{5} \].
08
Write the Final Answer
The roots of the equation \( x^2 + 2x = 4 \) are \( x = -1 + \sqrt{5} \) and \( x = -1 - \sqrt{5} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Standard Form
When working with quadratic equations, it's important to get the equation into a special format called Standard Form. This form is always written as \( ax^2 + bx + c = 0 \), where \( a \), \( b \), and \( c \) are numbers called coefficients.
To transform any quadratic equation into Standard Form, you might need to do some rearranging. For example, if you start with an equation like \( x^2 + 2x = 4 \), first move all terms to one side of the equation so that the other side equals zero. This means subtracting 4 from both sides:
Now, the equation becomes \( x^2 + 2x - 4 = 0 \), which is in Standard Form.
To transform any quadratic equation into Standard Form, you might need to do some rearranging. For example, if you start with an equation like \( x^2 + 2x = 4 \), first move all terms to one side of the equation so that the other side equals zero. This means subtracting 4 from both sides:
- Subtract 4 from both sides of the equation
Now, the equation becomes \( x^2 + 2x - 4 = 0 \), which is in Standard Form.
Coefficients
In the context of the quadratic equation in Standard Form \( ax^2 + bx + c = 0 \), coefficients are the numbers that multiply the variables. Understanding these coefficients is key to using the quadratic formula.
Let's break down their roles:
For example, in the equation \( x^2 + 2x - 4 = 0 \):
Let's break down their roles:
- \(a\): This is the coefficient of \(x^2\). It's the number in front of the \(x^2\) term.
- \(b\): This is the coefficient of \(x\). It’s the number attached to the \(x\) term.
- \(c\): This is the constant term; it has no variable attached to it.
For example, in the equation \( x^2 + 2x - 4 = 0 \):
- \(a = 1\), because it’s \(1\) times \(x^2\).
- \(b = 2\), because it’s \(2\) times \(x\).
- \(c = -4\), since it’s the constant, just \(-4\).
Discriminant
The discriminant is part of the quadratic formula and is found in the expression under the square root sign: \(b^2 - 4ac\). It gives valuable information about the nature of the roots of the quadratic equation.
Here's how to interpret the discriminant:
For the equation \(x^2 + 2x - 4 = 0\), the discriminant is calculated as follows:
Here's how to interpret the discriminant:
- If \(b^2 - 4ac > 0\), there are two distinct real roots.
- If \(b^2 - 4ac = 0\), there is exactly one real root (also known as a repeated root).
- If \(b^2 - 4ac < 0\), there are no real roots, only complex roots.
For the equation \(x^2 + 2x - 4 = 0\), the discriminant is calculated as follows:
- Using \(a = 1\), \(b = 2\), \(c = -4\)
- \(b^2 - 4ac = 2^2 - 4(1)(-4) = 4 + 16 = 20\)
Square Root Simplification
Simplifying square roots is crucial in solving quadratic equations using the quadratic formula, especially when dealing with irrational numbers. After calculating the discriminant \(b^2 - 4ac\), resulting in a number like 20, we need to simplify \(\sqrt{20}\).
Here's the process for simplifying square roots:
Applying this to the quadratic formula solution, \(x = \frac{-2 \pm \sqrt{20}}{2}\) becomes \(x = \frac{-2 \pm 2\sqrt{5}}{2}\), and further simplifies to \(x = -1 \pm \sqrt{5}\). This simplification step is key for expressing the roots in their simplest radical form.
Here's the process for simplifying square roots:
- Check if the number under the square root can be broken down into perfect square factors. For 20, it can be expressed as \(4 \times 5\).
- The square root of a product is equal to the product of the square roots: \(\sqrt{4 \times 5} = \sqrt{4} \times \sqrt{5}\).
- We know that \(\sqrt{4} = 2\), so \(\sqrt{20} = 2\sqrt{5}\).
Applying this to the quadratic formula solution, \(x = \frac{-2 \pm \sqrt{20}}{2}\) becomes \(x = \frac{-2 \pm 2\sqrt{5}}{2}\), and further simplifies to \(x = -1 \pm \sqrt{5}\). This simplification step is key for expressing the roots in their simplest radical form.