Chapter 4: Problem 21
In \(20-27\) : a. Write each equation in center-radius form. b. Find the coordinates of the center. . Find the radius of the circle. $$ x^{2}+y^{2}-2 x-2 y-7=0 $$
Short Answer
Expert verified
Center: (1, 1); Radius: 3.
Step by step solution
01
Reorganize the Equation
Start by rearranging the original equation to group the x terms and y terms together. This will help in completing the square later. The equation becomes: \[ x^2 - 2x + y^2 - 2y - 7 = 0 \]
02
Complete the Square for X
To complete the square for the \(x\) terms, take the coefficient of \(x\) which is \(-2\), divide by 2 to get \(-1\), and then square it to get \(1\). Add and subtract \(1\) inside the equation:\[ x^2 - 2x + 1 - 1 + y^2 - 2y - 7 = 0 \]
03
Complete the Square for Y
Do the same for the \(y\) terms. The coefficient of \(y\) is \(-2\), so divide by 2 to get \(-1\), and then square it to get \(1\). Add and subtract \(1\) as well:\[ x^2 - 2x + 1 + y^2 - 2y + 1 - 1 - 7 = 0 \]
04
Simplify and Factor
The terms can now be grouped and factored to indicate perfect squares. Combine the \(1\)s and \(-7\) on the right side:\[ (x - 1)^2 + (y - 1)^2 = 9 \]
05
Identify Center and Radius
The equation is now in the center-radius form \((x - h)^2 + (y - k)^2 = r^2\). Here, \(h = 1\), \(k = 1\), and \(r^2 = 9\), so the radius \(r = 3\). Therefore, the center is \((1, 1)\) and the radius is \(3\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Completing the Square
Completing the square is a method used to transform a quadratic expression into a perfect square trinomial. This is a crucial step for converting circle equations into a more familiar format. Here's how we do it:
- First, focus on the terms involving the variable, such as the terms with "x" or "y".
- Take the coefficient of the linear term, divide it by 2, and then square the result. This helps turn the quadratic expression into a perfect square trinomial.
- Add and subtract this squared number within the equation to keep it balanced.
Center-Radius Form
Once the square for both x and y terms are completed, the equation of the circle can be rewritten in a neat form called the center-radius form. This form clearly presents both the center of the circle and the radius. The standard center-radius form of a circle's equation is:
- \((x - h)^2 + (y - k)^2 = r^2\)
- \((x-1)^2 + (y-1)^2 = 9\)
Equation of a Circle
The general equation for a circle in a plane is derived from its geometric definition. It represents all the points that are equidistant from a given point, called the center. A circle's equation is expressed as:
- \(x^2 + y^2 + Dx + Ey + F = 0\)
Geometry of Circles
Understanding the geometry of circles is crucial in many mathematical contexts, from basic geometry to advanced calculus. A circle is defined as a set of points in a plane, all equally distant from a central point. This distance is referred to as the radius. The central point is the center.
The basic geometric properties of a circle include:
The basic geometric properties of a circle include:
- The center \( (h, k) \)
- The radius \( r \)
- A perfectly symmetric shape where every diameter measures twice the length of the radius