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a. Draw the graphs of \(y=|x+3|\) and \(y=5\) b. From the graph drawn in a, determine the solution set of \(|x+3|=5 .\) C. From the graph drawn in a, determine the solution set of \(|x+3| > 5\) d. From the graph drawn in a, determine the solution set of \(|x+3| < 5\)

Short Answer

Expert verified
a. Graph of \( y=|x+3| \) is a V-shape, intersecting the line \( y=5 \) at \( x=2 \) and \( x=-8 \). b. Solutions: \( x = 2 \) and \( x = -8 \). c. Solution: \( x < -8 \) or \( x > 2 \). d. Solution: \( -8 < x < 2 \).

Step by step solution

01

Understanding and Sketching \( y = |x+3| \)

The function \( y = |x+3| \) is a V-shaped graph. The expression \( x+3 \) indicates a horizontal shift 3 units to the left from the standard \( y = |x| \). The vertex of the graph is at \((-3, 0)\), and it opens upwards. Sketch the graph with this vertex and ensure the slope is +1 for \( x > -3 \) and -1 for \( x < -3 \).
02

Sketching the Line \( y = 5 \)

The line \( y = 5 \) is a horizontal line passing through all points where the y-coordinate is 5. Draw a straight line parallel to the x-axis at y=5 on the graph you have sketched so far.
03

Solving \( |x+3| = 5 \) Graphically

Find points where the graph of \( y = |x+3| \) intersects the line \( y = 5 \). These intersections occur at \( x-2 \) and \( x=-8 \). The solution set is where the x-values satisfy \( |x+3| = 5 \). Therefore, the solution is \( x = 2 \) and \( x = -8 \).
04

Solving \( |x+3| > 5 \) Graphically

Following the graph, \( |x+3| > 5 \) corresponds to the regions where the V-shaped graph lies above the horizontal line \( y = 5 \). The solution set occurs for \( x < -8 \) and \( x > 2 \).
05

Solving \( |x+3| < 5 \) Graphically

From the graph, \( |x+3| < 5 \) corresponds to the region where the V-shaped graph lies below the horizontal line \( y = 5 \). This region is between the intersections, resulting in the interval \( -8 < x < 2 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Graphing Absolute Value Functions
Understanding how to graph absolute value functions like \( y = |x+3| \) is quite simple. Absolute value functions are characterized by their V-shaped graphs. The function \( y = |x+3| \) derives from a basic absolute value function \( y = |x| \) which is centered at the origin. Because \( x+3 \) is inside the absolute value, it indicates a horizontal shift to the left by 3 units. Therefore, you plot the vertex of the graph at \((-3, 0)\).

The arms of the V-shaped graph open upwards, following a slope of +1 for \( x > -3 \) and a slope of -1 for \( x < -3 \). To draw the graph of \( y=|x+3| \), just mark the vertex and sketch two lines at these slopes starting from the vertex. The graph is symmetrical around the vertex, creating a characteristic V shape. To represent \( y=5 \), simply draw a straight, horizontal line across the y-axis at the 5-unit mark.
Solution Sets
Solution sets in the context of absolute value equations come from understanding where two graphs intersect. Looking at \( y = |x+3| \) and \( y = 5 \), the solution to \( |x+3| = 5 \) is determined by finding the x-values where these two lines cross.

The function \( y=|x+3| \) intersects with \( y=5 \) at two points. By observing the graph, you can find these points at \( x = 2 \) and \( x = -8 \). By solving algebraically or simply observing the intersections graphically, these values constitute the solution set for the equation \( |x+3| = 5 \).

Solution sets are the specific x-values that satisfy given equations. They are determined from where the absolute value graph intersects or fails to intersect with another function, like a horizontal line. These points highlight all the possible x-values that solve the equation at hand.
Inequalities with Absolute Values
Inequalities involving absolute values, such as \( |x+3| > 5 \) or \( |x+3| < 5 \), describe different regions of the graph due to its V shape. For the inequality \( |x+3| > 5 \), you are looking for the parts of the V-shaped graph that are *above* the horizontal line \( y = 5 \).

On the graph, these conditions occur at both tails of the V, away from the vertex. Specifically, this inequality holds for \( x < -8 \) and \( x > 2 \). Conversely, the inequality \( |x+3| < 5 \) seeks where the graph is *below* the horizontal line. This happens between the intersections, specifically within the interval \( -8 < x < 2 \).

These inequalities define which sections of the x-axis are solutions to the inequality, essentially providing a range of values that satisfy the conditions. Understanding these solutions graphically helps to see not just points of equality, but full ranges of x-values where the graph meets, exceeds, or undercuts the given line.

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