Chapter 3: Problem 47
In \(43-47,\) express each answer in simplest radical form. The dimensions of a rectangle are \(\sqrt{250}\) meters and \(\sqrt{1,440}\) meters. a. Express the perimeter of the rectangle in simplest radical form. b. Express the length of the diagonal of the rectangle in simplest radical form.
Short Answer
Expert verified
Perimeter: \( 34\sqrt{10} \) meters; Diagonal: \( 13\sqrt{10} \) meters.
Step by step solution
01
Understand the problem
We are given a rectangle with side lengths of \( \sqrt{250} \) meters and \( \sqrt{1440} \) meters. We need to find two things: (a) the perimeter and (b) the length of the diagonal in simplest radical form.
02
Calculate the Perimeter
The perimeter \( P \) of a rectangle is calculated using the formula \( P = 2(l + w) \), where \( l \) is the length and \( w \) is the width. Here, \( l = \sqrt{250} \) and \( w = \sqrt{1440} \). Therefore,\[ P = 2(\sqrt{250} + \sqrt{1440}). \] We need to simplify \( \sqrt{250} \) and \( \sqrt{1440} \) by finding their prime factors.
03
Simplify Each Square Root
To simplify \( \sqrt{250} \), note that 250 can be expressed as \( 25 \times 10 = 5^2 \times 2 \). Thus, \( \sqrt{250} = \sqrt{5^2 \times 10} = 5\sqrt{10} \). To simplify \( \sqrt{1440} \), note that 1440 can be expressed as \( 144 \times 10 = 12^2 \times 10 \). Thus, \( \sqrt{1440} = \sqrt{12^2 \times 10} = 12\sqrt{10} \).
04
Substitute Simplified Radicals into Perimeter Formula
Substitute the simplified forms into the formula for the perimeter: \[ P = 2(5\sqrt{10} + 12\sqrt{10}) = 2(17\sqrt{10}). \]This simplifies to: \[ P = 34\sqrt{10}. \]
05
Calculate the Diagonal Using the Pythagorean Theorem
The diagonal \( d \) of a rectangle is found using the Pythagorean theorem: \[ d^2 = l^2 + w^2. \] Hence, \[ d^2 = (5\sqrt{10})^2 + (12\sqrt{10})^2 = 250 + 1440. \]
06
Compute the Diagonal
Calculate \( d^2 = 250 + 1440 = 1690. \) The diagonal \( d \) is therefore \( \sqrt{1690} \). We need to simplify \( \sqrt{1690} \) further.
07
Simplify the Diagonal
The number 1690 can be expressed in terms of its prime factors: \( 1690 = 169 \times 10 = (13^2) \times 10 \). Thus, \[ \sqrt{1690} = \sqrt{(13^2) \times 10} = 13\sqrt{10}. \]
08
Conclusion
The perimeter of the rectangle in simplest radical form is \( 34\sqrt{10} \) meters, and the length of the diagonal is \( 13\sqrt{10} \) meters.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Perimeter of a Rectangle
When we talk about the perimeter of a rectangle, we're referring to the total distance around the rectangle. The formula for calculating the perimeter is simple:
- The formula is given by \( P = 2(l + w) \), where \( l \) is the length and \( w \) is the width of the rectangle.
- This formula effectively adds up all the sides of the rectangle. There are two lengths and two widths, which is why we multiply the sum by \( 2 \).
Diagonal of a Rectangle
In any rectangle, the diagonal is the line segment that connects opposite corners. This diagonal splits the rectangle into two right-angled triangles.To find the length of the diagonal, we often use the relationship from the properties of right triangles:
- The Pythagorean Theorem.
Pythagorean Theorem
The Pythagorean Theorem is a fundamental principle in geometry for right-angled triangles. It's expressed as \( a^2 + b^2 = c^2 \), where \( c \) is the hypotenuse (the longest side of the triangle), and \( a \) and \( b \) are the other two sides. Here's how it works:
- In a rectangle, the diagonal acts as the hypotenuse of a right triangle.
- The two sides of the rectangle are the other two sides of the triangle.
- By applying the theorem, you can find the length of the diagonal.
Prime Factors
Prime factorization involves breaking down a number into the prime numbers that multiply together to make it. For instance, 250 can be split into prime factors as \( 5^2 \times 2 \). Simplifying radicals often involves prime factorization.Why prime factors?
- Prime factors help in simplifying complex square roots by identifying perfect squares within them.
- If you can find a perfect square within a number, it can be simplified outside the radical.
- For example, \( \sqrt{250} = \sqrt{5^2 \times 10} = 5\sqrt{10} \).