Chapter 2: Problem 17
Solve each proportion for the variable. \(\frac{4 x-8}{3}=\frac{8}{x-3}\)
Short Answer
Expert verified
The solution is \( x = 5 \).
Step by step solution
01
Identify the Proportion
The given exercise is a proportion - two fractions set equal to each other. The problem is \( \frac{4x-8}{3} = \frac{8}{x-3} \). We need to solve this proportion for the variable \( x \).
02
Cross-Multiply the Fractions
To solve the proportion, start by cross-multiplying the fractions. This means multiply the numerator of the first fraction by the denominator of the second fraction and vice versa. This gives us \( (4x - 8)(x - 3) = 8 \times 3 \).
03
Simplify and Multiply
First, compute the multiplication on the right side of the equation: \[ 8 \times 3 = 24 \]Next, apply the distributive property to the left side:\[ (4x - 8)(x - 3) = 4x(x) - 4x(3) - 8(x) + 8(3) \]This simplifies to:\(4x^2 - 12x - 8x + 24\).
04
Combine Like Terms
Now, combine like terms in the equation:\[ 4x^2 - 12x - 8x + 24 = 24 \]This simplifies to:\[ 4x^2 - 20x + 24 = 24 \].
05
Set Up and Simplify the Quadratic Equation
Subtract 24 from both sides to form the standard quadratic equation:\[ 4x^2 - 20x + 24 - 24 = 0 \]This simplifies to:\[ 4x^2 - 20x = 0 \].
06
Factor the Quadratic Equation
Factor out the common term from the quadratic equation:\[ 4x(x - 5) = 0 \].
07
Solve for the Roots
Set each factor equal to zero:1. \( 4x = 0 \) gives \( x = 0 \).2. \( x - 5 = 0 \) gives \( x = 5 \).
08
Verify the Solutions
To ensure both solutions are valid, substitute back into the original proportion. For \( x = 0 \), the denominator becomes negative or undefined, so it is invalid in the context of the original equation. Verify for \( x = 5 \): - Substitute \( x = 5 \) into the original equation: - Left side: \( \frac{4(5) - 8}{3} = \frac{12}{3} = 4 \) - Right side: \( \frac{8}{5-3} = \frac{8}{2} = 4 \) Both sides equal, confirming \( x = 5 \) is a valid solution.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cross-Multiplication
Cross-multiplication is a wonderful tool for solving proportions. When you have two fractions set equal to one another, like \( \frac{4x-8}{3} = \frac{8}{x-3} \), you can use cross-multiplication. The key idea is to multiply the diagonal terms. Here's how it works:
Just remember, cross-multiplying helps balance the scales, turning a fraction-filled equation into something more approachable.
- Multiply the numerator of the first fraction by the denominator of the second: \((4x - 8)(x - 3)\).
- Multiply the numerator of the second fraction by the denominator of the first: \(8 \times 3\).
Just remember, cross-multiplying helps balance the scales, turning a fraction-filled equation into something more approachable.
Quadratic Equation
A quadratic equation is any equation that can be rearranged into the standard form \(ax^2 + bx + c = 0\). In our scenario, after applying the distributive property and simplifying, we obtained \(4x^2 - 20x = 0\). This qualifies as a quadratic equation because it features a term with \(x^2\), a linear term \(x\), and a constant term, which is zero in this simplified case.
- To solve a quadratic equation, look for methods such as factoring, the quadratic formula, or completing the square.
- Quadratic equations often have two solutions, corresponding to the points where the graph intersects the x-axis.
Distributive Property
The distributive property is a nifty tool that helps simplify expressions that involve multiplying a term by a binomial, like \((4x - 8)(x - 3)\). It's written as \(a(b + c) = ab + ac\). Here's what we did:
- Multiply each term inside the parenthesis by \(4x\): \(4x \cdot x\) and \(4x \cdot -3\).
- Multiply each term by \(-8\): \(-8 \cdot x\) and \(-8 \cdot -3\).
Factoring Quadratics
Factoring quadratics is the process of breaking down a quadratic equation into a product of simpler terms. In our case, \(4x^2 - 20x = 0\) was factored into \(4x(x - 5) = 0\). Factoring tells us the values of \(x\) that make the equation equal to zero.Here's a step-by-step discussion:
- First, identify a common factor from all the terms and factor it out, here it was \(4x\).
- Then, see what's left inside the parenthesis and factor further if possible, yielding \(x - 5\).