Chapter 14: Problem 26
For each \(\triangle O R S, O\) is the origin, \(R\) is on the positive ray of the \(x\) -axis and \(\overline{P S}\) is the altitude from \(S\) to \(\overrightarrow{O R}\) . Find the exact coordinates of \(R\) and \(S .\) b. Find the exact area of \(\triangle O R S .\) \(O R=8, \mathrm{m} \angle R O S=\frac{3 \pi}{4}, O S=8\)
Short Answer
Step by step solution
Identify Triangle Components
Find Coordinates of S
Verify the Altitude Condition
Determine the Area of \(\triangle ORS\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cartesian Coordinates
In the triangle \( riangle ORS\), point O is at the origin. This simplifies determining the coordinates of point R which lies on the x-axis. Since O is at (0, 0) and the distance OR is 8 units, R is simply at the point (8, 0). These are easy to visualize as movement along the x-axis without any change in the y-coordinate.
Using Cartesian coordinates allows us to break down problems into smaller, more manageable steps. It's like having a precise roadmap that tells you exactly where each point of interest is located.
Polar Coordinates
For point S in \( riangle ORS\), we've been given that the distance (r) from the origin O is 8, and the angle (θ) with the positive x-axis is \(\frac{3\pi}{4}\). To convert polar coordinates \(8, \frac{3\pi}{4}\) into Cartesian coordinates, we use the formulas:
- \(x = r \cos(\theta)\)
- \(y = r \sin(\theta)\)
Inserting the given values, we compute the coordinates of S as \(-4\sqrt{2}\) for x and \(+4\sqrt{2}\) for y, resulting in Cartesian coordinates of \((-4\sqrt{2}, 4\sqrt{2})\).
Polar coordinates are particularly useful in scenarios involving circles and angles, providing an intuitive understanding of how points relate to each other based on their direction and distance from a central point.
Triangle Area Calculation
\[ A = \frac{1}{2} \times \text{base} \times \text{height} \]
In the example of \( riangle ORS\), the base is the line segment OR, which measures 8 units. The height is determined by the y-coordinate of point S, which is \(+4\sqrt{2}\). Using these values in the formula gives:
- \(A = \frac{1}{2} \times 8 \times 4\sqrt{2} = 16\sqrt{2}\)
This result shows how effectively using the properties of triangles allows us to calculate their areas precisely. Understanding the orientation of triangles within coordinate planes simplifies the process significantly.
Algebra 2 Concepts
Finding polar coordinates and understanding their conversion to Cartesian coordinates requires the application of trigonometric functions from Algebra 2. When given an angle like \(\frac{3\pi}{4}\), being familiar with the sine and cosine functions allows us to find the precise x and y coordinates through:
- \(x = r \cos(\theta)\)
- \(y = r \sin(\theta)\)
By extending these concepts, students can easily interconnect different mathematical disciplines and apply them in various contexts from physics to computer graphics, showcasing the importance of a thorough understanding of these algebraic methods.