Chapter 13: Problem 6
In \(3-14\) , use the quadratic formula to find, to the nearest degree, all values of \(\theta\) in the interval \(0^{\circ} \leq \theta<360^{\circ}\) that satisfy each equation. $$ 9 \sin ^{2} \theta+6 \sin \theta=2 $$
Short Answer
Expert verified
The values of \(\theta\) are \(14^{\circ}\) and \(166^{\circ}\).
Step by step solution
01
Identify the equation in standard quadratic form
The given equation is \(9 \sin^2 \theta + 6 \sin \theta = 2\). This can be rearranged to the standard quadratic form as \(9 \sin^2 \theta + 6 \sin \theta - 2 = 0\). The equation is in terms of \(\sin \theta\), where \(a = 9\), \(b = 6\), and \(c = -2\).
02
Use the quadratic formula
The quadratic formula is \( \sin \theta = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \). Plugging in the values of \(a\), \(b\), and \(c\), we get \( \sin \theta = \frac{-6 \pm \sqrt{6^2 - 4 \times 9 \times (-2)}}{2 \times 9} \).
03
Calculate the discriminant and roots
Calculate the discriminant: \(b^2 - 4ac = 6^2 - 4 \times 9 \times (-2) = 36 + 72 = 108\). Now compute the square root of the discriminant: \(\sqrt{108} = \sqrt{36 \times 3} = 6\sqrt{3}\). Substitute back into the quadratic formula to find: \( \sin \theta = \frac{-6 \pm 6\sqrt{3}}{18}\). Simplify the roots to get: \( \sin \theta = \frac{-1 \pm \sqrt{3}}{3}\).
04
Determine the valid sine values
The possible solutions for \(\sin \theta\) are \(\sin \theta = \frac{-1 + \sqrt{3}}{3}\) and \(\sin \theta = \frac{-1 - \sqrt{3}}{3}\). Evaluate these numerically: \(\frac{-1 + \sqrt{3}}{3} \approx 0.244\) and \(\frac{-1 - \sqrt{3}}{3} < -1\), which is invalid as \(\sin \theta\) must be between \(-1\) and \(1\).
05
Find angles for valid \(\sin \theta\)
Consider \(\sin \theta = 0.244\) which is valid. The solution exists in the first and second quadrants. Calculate: \(\theta_1 \approx \arcsin(0.244) \approx 14.1^{\circ}\) and \(\theta_2 = 180^{\circ} - 14.1^{\circ} = 165.9^{\circ}\), rounding to the nearest degree gives \(\theta = 14^{\circ}\) and \(\theta = 166^{\circ}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding the Sine Function
The sine function is fundamental in trigonometry, representing the y-coordinate of a point on the unit circle as the angle in radians or degrees changes. It describes how the height of a point above the horizontal axis varies as we move around the circle.
For any angle \( \theta \), the sine function gives us \( \sin(\theta) \), which ranges between -1 and 1. This is crucial because any acceptable solution for \( \sin \theta \) must lie within these bounds.
In the unit circle:
For any angle \( \theta \), the sine function gives us \( \sin(\theta) \), which ranges between -1 and 1. This is crucial because any acceptable solution for \( \sin \theta \) must lie within these bounds.
In the unit circle:
- \( \sin(0^\circ) = 0 \)
- \( \sin(90^\circ) = 1 \)
- \( \sin(180^\circ) = 0 \)
- \( \sin(270^\circ) = -1 \)
Solving a Trigonometric Equation
A trigonometric equation often involves trigonometric functions like sine, cosine, or tangent set equal to a value. The goal is to find all the angle measures within a specified interval that satisfy this equation. For example, in our exercise, we have the equation \[9 \sin^2 \theta + 6 \sin \theta - 2 = 0,\]which breaks down into working with \( \sin \theta \).
This equation mirrors the structure of a quadratic equation \( ax^2 + bx + c = 0 \). Identifying this helps us apply algebraic techniques, such as the quadratic formula, traditionally used on quadratic expressions.
To solve:
This equation mirrors the structure of a quadratic equation \( ax^2 + bx + c = 0 \). Identifying this helps us apply algebraic techniques, such as the quadratic formula, traditionally used on quadratic expressions.
To solve:
- Express it in standard form: \(9 \sin^2 \theta + 6 \sin \theta - 2 = 0\).
- Isolate \( \sin \theta \) using the quadratic formula.
- Evaluate resulting values to see which are within the acceptable range of sine.
Discriminant Calculation in Quadratic Equations
The discriminant of a quadratic equation \( ax^2 + bx + c = 0 \) is given by \( b^2 - 4ac \). This value is crucial because it determines the nature and number of roots or solutions of the equation.
Here's how the discriminant impacts solutions:
Here's how the discriminant impacts solutions:
- If the discriminant is positive, there are two distinct real roots.
- If it is zero, there is exactly one real root (repeated).
- If negative, there are no real roots—only complex ones.